A really close answer-why? (conter of mass)

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SUMMARY

The discussion focuses on calculating the center of mass (COM) of a water molecule, consisting of one oxygen atom and two hydrogen atoms. The mass of the oxygen atom is 16 times that of a hydrogen atom, and the bond lengths and angles are specified. The calculated x-coordinate of the COM is 0.0067 nm, while the expected answer is 0.00669 nm, highlighting the importance of precision in calculations. The discrepancy arises from rounding errors in the trigonometric calculations of the hydrogen atom coordinates.

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Homework Statement



A water molecule consists of an oxygen atom with two hydrogen atoms bound to it as shown in Figure P8.8. The bonds are 0.100 nm in length and the angle between the two bonds is 106°. Use the coordinate axis shown and determine the location of the center of gravity of the molecule. Take the mass of an oxygen atom to be 16 times the mass of hydrogen.

p8-8.gif


Homework Equations



y com = [tex]\Sigma mixi[/tex] / [tex]\Sigma mi[/tex]
Same with x

The Attempt at a Solution



Let mass of H atom =m, Mass of O atom = 16m

Coordinates of upper H = (0.100cos 53, 0.100 sin 53) (in nm) = (0.06,0.08)
Coordinates of lower H = (0.06,-0.08)
Coorinates of O=(0,0)

x-coordinate of COM = sum of (mass of each particle* its x coordinate ) for each particle , divided by total mass = (1/M)Σmixi

Here total mass M = m+m+16m = 18m
∴xCOM = (m*0.06+m*0.06+0)/18m = 0.12/18 = 0.0067 nm

Similarly , yCOM = ((m*0.08) + m*(-0.08) +0)/18 m = 0 nm

∴ COM of molecule = (0.0067 nm, 0)
-------------------------------------------------------

But the answer is 0.00669, not 0.0067. And according to me calculator, it is 0.006666667.
Where did 0.0069 came from?
 
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Coordinates of upper H = (0.100cos 53, 0.100 sin 53) (in nm) = (0.06,0.08)

If you want 2 digit accuracy in the answer, you should record
.1*cos(53) as 0.0602
 
Ah.. I see. ^_^ That tiny bit of omission makes answer different. I was curious because the homework required me to express very accurately. Thanks!
 

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