A sample of normal RVs - the distribution of Xi-Xbar?

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The discussion focuses on determining the distribution of the difference between a normal random variable \(X_1\) and the sample mean \(\bar{X}\) of \(n\) independent normal random variables \(X_1, \ldots, X_n \sim N(\mu, \sigma^2)\). It establishes that \(\bar{X} \sim N(\mu, \sigma^2/n)\) and seeks to find the distribution of \(X_1 - \bar{X}\). The conclusion reached is that \(X_1 - \bar{X} \sim N(0, (1 + 1/n)\sigma^2)\), confirming the variance as \((1 + 1/n)\sigma^2\).

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We have X1,...,Xn~N(mu, sigma2)

The crux of my problem is finding out the distribution of, say, X1-Xbar (where Xbar is the mean of the n RVs). This is going to end up proving the independence of Xbar and Sxx, btw.

I know Xbar~N(mu, sigma2/n), but I don't know how to find the distribution of a difference of normal RVs with different arguments?

Thanks for any help.
 
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Notice that

<br /> X_1 - \bar X = (1-\frac 1 n) X_1 - \frac 1 n \sum_{i\ge2}X_i<br />

and all of X_1 and X_2, \dots, X_n are independent.

* Get the distribution of

(1 - \frac 1 n) X_1<br />

as well as that of

<br /> \frac 1 n \sum_{n\ge2} X_i<br />

These are independent as well, so find the distribution of their difference.
 
I have Xi-Xbar ~ N(0, (1+1/n)sigma2) ?
 
Are you sure the variance is

<br /> \left(1 + \frac 1 n \right) \sigma^2<br />
 

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