A simple question about Covalent Bond and Ionic Bond

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SUMMARY

This discussion centers on the comparison of covalent bonds in cuprous chloride (CuCl) and cupric chloride (CuCl2), focusing on the concept of variable valencies. In CuCl, copper exhibits a valency of one, forming a covalent bond with chlorine, which takes one electron, resulting in a +1 charge for copper and a -1 charge for chlorine. In CuCl2, copper has a valency of two, leading to two chlorine atoms each taking one electron, resulting in a +2 charge for copper. The bond strength comparison reveals that while the bond dissociation energy for CuCl is higher than that for CuCl2, the overall trend indicates that higher oxidation states in transition metals generally lead to easier removal of halides.

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  • Familiarity with bond dissociation energy concepts
  • Basic principles of oxidation states in chemistry
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JasonRox
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I started reading a book about the basic foundations of chemistry, and I came up across a simple question.

To answer this question you should understand that there are variable valencies, which is what this question consists of.

If you look at the cuprous chloride compound CuCl, copper has a valency of one.

Chlorine will "take" an electron from the Copper atom, which forms a covalent bond. When taking the electron the overall magnetic charge of the chlorine atom is negative (let's say -1), and Copper is now overall positive (+1).

If we look at a slightly different compound cupric chloride CuCl(2), copper has a valency of 2.

Chlorine 1 and 2 will now take each an electron, so you have two with an overall charge of -1. Copper now gives two away, on its own, and now has an overall charge of +2.

My question is...

Is one bond stronger than the other because of magnetic charge?

In other words, would Chlorine be easier to isolate from the CuCl compound than the CuCl(2) compound, or molecule?

Thanks, for any answers.
 
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Anyone?

This is a simple question in which I am pondering.
 
I'm not sure because I'm no expert but I think that the Cu-Cl bond is identical regardless of how many bonds there are. So it'd require just as much energy to break any Cu-Cl bond.
 
chemistry always contains of mystery...
 
JasonRox said:
I started reading a book about the basic foundations of chemistry, and I came up across a simple question.

To answer this question you should understand that there are variable valencies, which is what this question consists of.

If you look at the cuprous chloride compound CuCl, copper has a valency of one.

Chlorine will "take" an electron from the Copper atom, which forms a covalent bond. When taking the electron the overall magnetic charge of the chlorine atom is negative (let's say -1), and Copper is now overall positive (+1).

You are referring to an electric charge... not magnetic.

If we look at a slightly different compound cupric chloride CuCl(2), copper has a valency of 2.

Chlorine 1 and 2 will now take each an electron, so you have two with an overall charge of -1. Copper now gives two away, on its own, and now has an overall charge of +2.

My question is...

Is one bond stronger than the other because of magnetic (electric) charge?

In other words, would Chlorine be easier to isolate from the CuCl compound than the CuCl(2) compound, or molecule?

Thanks, for any answers.

Let's look at trends in the transition metal halide series


Bond Bond dissociation energy (kJmol-1)
Ti-Cl (TiCl4) 429.3
Ti-Cl (TiCl3) 460.2
Ti-Cl (TiCl2) 504.6
Fe-F (FeF3) ~456
Fe-F (FeF2) 481
Fe-Cl (FeCl3) 341.4
Fe-Cl (FeCl2) 400.0
Fe-Br (FeBr3) 291.2
Fe-Br (FeBr2) 339.7
Fe-I (FeI3) 233.5
Fe-I (FeI2) 279.1
Cu-Cl (CuCl2) 293.7
Cu-Cl (CuCl) 360.7
Cu-Br (CuBr2) ~259
Cu-Br (CuBr) 330.1
Cu-I (CuI2) ~192
Cu-I (CuI) ~142

Clearly the trend is that the higher the oxidation state, the easier it is to remove the first halide in transition metals.
 
Necrophilia :smile:
 
A thread dig from 2004? That was long before I was even a member here
 
Opps! I keep forgetting to check that...
 

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