A small task with Newton's Laws

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Homework Help Overview

The discussion revolves around a physics problem involving Newton's Laws, specifically related to the motion of an object in free fall. The scenario involves Santa dropping packages from a height while flying at a high speed, requiring calculations for both the time it takes for the package to fall and the distance Santa should be from the chimney when releasing the package.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the time it takes for the package to fall using gravitational equations and question the trajectory of the package when released at high speed. There is discussion about the relationship between the speed of the package and the distance it will travel horizontally while falling.

Discussion Status

Some participants have provided calculations for the fall time and the distance from which Santa should release the package. There is acknowledgment of the results, but questions remain about the accuracy and interpretation of the physics involved, particularly regarding the trajectory of the falling package.

Contextual Notes

Participants are working under the assumption that air resistance can be ignored, and there is a focus on ensuring precision in the calculations to meet the requirements of the problem.

Jirya
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Homework Statement



I have been given a small task. There is two parts. (I have translated it from another language):

"Santa is flying in his sleigh 836,6 feet (250 meters) above the ground. To save time, he will let the packets fall from the sack down the chimney of a house. The package is not broken by this treatment as Santa Claus, knows a top-secret trick. The chimney he must frame is 10 meter (32,8 feet tall.)

How long does it take the package to drop down the chimney?

To save the most time a efficiency pixie suggests that Santa must let go of the packages while he is at full speed instead of stopping. Thus he doesn't need to stop at each house.

Your task now is to help Santa to determine where he will let go of the package, so that it hits its target. Remember to be precise - otherwise there are no gifts for Christmas!

It is reported that the slide speed is 1200 km / h, and that can be ignored air resistance - this is another one of Santa's hitherto secret tricks.

Homework Equations



Okay. I know I need to use Newton's Law about gravitation - and I need the accelaration.

The Attempt at a Solution



I have an idea about the first task, but i am lost with the second.

I can find the fall time with this equation:
h = ½·g·t^2

Then I just have to isolate for t.

t^2=h / ½ / g
t^2 = 240 meter / ½ / 9,82
t^2 = 48,87
t = √48,87
t = 6,99 ≈ 7 seconds
 
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Welcome to PF;
Jirya said:
I have an idea about the first task, but i am lost with the second.
if Santa were to drop the presents from directly above the chimney - they would miss! Why?
 
Simon Bridge said:
Welcome to PF;
if Santa were to drop the presents from directly above the chimney - they would miss! Why?

Thank you.

Hey, It made me think about something.

I guess, you would miss, because the object will fall with a parabolic trajectory in the same direction the plane is flying.

But ..

Doesn't the object have the same speed as Santa Claus? in this case 1200 km/hour?

So now I have the speed of the package and the time it takes to fall down. That means that I can solve this easily with this equation:

t * v = distance

So I just have to calculate how far the package will move in 7 seconds, which is 2.3 kilometers. Or am I wrong?

* I have attached a small graphic

Screen Shot 2014-01-01 at 08.58.08.png
 
It is correct.

ehild
 
Just to make sure.

How long does it take the package to drop down the chimney?
- Around 7 seconds.

Your task now is to help Santa to determine where he will let go of the package, so that it hits its target.
- 2333.333 meters before the chimney.

Can one of you confirm that these results are correct?

And by the way, thank you very much for your help Simon and ehild.
 
It is 2333 m before reaching above the chimney. -2333 m before is 2333 m after.:smile:

ehild
 
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ehild said:
It is 2333 m before reaching above the chimney. -2333 m before is 2333 m after.:smile:

ehild


Oh, the "-" was not written on purpose. But thank you for the heads up! :)

Have a great day.
 
Happy New Year to you!:smile:


ehild
 
Well done :)
 

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