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Yes, but expand that net force into a sum of forces.HJ^2 said:Forgot I had already incorporated 9.8 (gravity) already, my mistake.
Since acceleration is the result of NF; would it not be mass * acc (f=ma)
The discussion revolves around a physics problem involving a person falling from a height and the forces exerted by the ground upon landing. The subject area includes concepts from mechanics, specifically kinematics and dynamics, as participants explore the calculations related to force, acceleration, and velocity during the impact.
The discussion is ongoing, with participants providing various calculations and questioning the validity of the given answer in the problem statement. Some participants have suggested alternative methods and highlighted potential inaccuracies in the problem setup, while others are still working through their understanding of the concepts involved.
Participants note discrepancies in the problem's parameters, such as the accuracy of time measurements and the implications of bending knees during the landing. There is also a recognition that the problem may not accurately reflect real-life scenarios, prompting discussions about the assumptions made in the calculations.
Yes, but expand that net force into a sum of forces.HJ^2 said:Forgot I had already incorporated 9.8 (gravity) already, my mistake.
Since acceleration is the result of NF; would it not be mass * acc (f=ma)
okay; sum of forces, as in, Fnet = m*a of which Fnet covers x / y values like friction, gravity, normal force? Am I missing something?haruspex said:Yes, but expand that net force into a sum of forces.
Sure, but write out what Fnet is here, in terms of normal force etc. There are only vertical forces involved, so it's easy. Remember, the normal force is what you are asked to find, so it's an unknown at this stage.HJ^2 said:okay; sum of forces, as in, Fnet = m*a of which Fnet covers x / y values like friction, gravity, normal force? Am I missing something?
So fnet would equal Fg + Fn = m*aharuspex said:Sure, but write out what Fnet is here, in terms of normal force etc. There are only vertical forces involved, so it's easy. Remember, the normal force is what you are asked to find, so it's an unknown at this stage.
Right. The only unknown there is Fn. Solve.HJ^2 said:So fnet would equal Fg + Fn = m*a
Fn = (m*a) - Fgharuspex said:Right. The only unknown there is Fn. Solve.
Fg is not 9.8 For one thing, it will be negative (since you have chosen up as positive).HJ^2 said:Fn = (m*a) - Fg
With variables is;
Fn = (74.4 * 6.8411) - 9.8 = 499.177 ?
haruspex said:Fg is not 9.8 For one thing, it will be negative (since you have chosen up as positive).
Right (but shared across two feet).HJ^2 said:Fgrav = -9.8*74.4?
If that's right, then;
Fn = (74.4*6.8411) - (-729.12) = 1238.10
Absolutely. I'll have to bring it up to her as I'm sure my class mates had similar concerns.haruspex said:Right (but shared across two feet).
So, do you see where your prof went wrong?
Good.HJ^2 said:Absolutely. I'll have to bring it up to her as I'm sure my class mates had similar concerns.
Oh thanks! And thank you so much for your help + everyone else in this thread :)haruspex said:Good.
On a side note, if you calculate how far the athlete's mass centre must travel after touch down and before coming to rest, it's about 3m!