A very Inquisitive question - Finding Force of Tension

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Homework Help Overview

The discussion revolves around a problem involving the forces of tension in a string, specifically focusing on the y-components of tension and their relation to the force of gravity. Participants are examining the setup of the problem, which includes a person on a rope and the associated distances and angles.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the use of trigonometric ratios and Newton's second law in their attempts to analyze the forces. There are questions regarding the clarity of the problem statement, particularly about the number of ropes involved and the distances mentioned. Some participants express confusion about the wording and its implications for solving the problem.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the problem's setup and exploring different interpretations of the information provided. Some have offered insights into the forces acting in the y-direction, while others are questioning the horizontal components and the overall understanding of the scenario.

Contextual Notes

There are noted ambiguities in the problem statement, particularly regarding the number of ropes and the distances involved. Participants are working with paraphrased information, which may contribute to the confusion surrounding the problem's setup.

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Homework Statement



Problem in Picture, I'm looking for the two forces of tension in the string, I expect the y-components to add to equal the force of gravity

Homework Equations


I used simple trig ratios to get the distances and angles.
Mainly using Newtons second law F = ma

The Attempt at a Solution


here is a link at my attempt, I'm simply stumped beyond this point.

http://ioj.com/v/ytyqh

website is an image uploader
 
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help is greatly appreciated !

I'm helping out others in the meantime here
 
Sorry, I am confused. The question first says "the rope", and then it says "two ropes". Are there just one or two? And it also says "5 m from on the rope from one side of the building". Shouldn't it be the horizontal distance of the person from the building and not the length of the rope from the building to the point where the person stands?
 
benhou said:
Sorry, I am confused. The question first says "the rope", and then it says "two ropes". Are there just one or two? And it also says "5 m from on the rope from one side of the building". Shouldn't it be the horizontal distance of the person from the building and not the length of the rope from the building to the point where the person stands?

Sorry for the wording, it must have caused the confusion. I don't have the question on hand so I am paraphrasing it as best as i Can. It says that a person (unrealistically) jumps onto a tight rope 5m away from its start ( total distance of rope is 17m, hence the 5m and 12 m sides ).

So yes i believe you should be solving for two separate tensions ( of one rope ) , the tension in the 5m length and the tension on the 12 m length
This question is a little tricky only because it is not in the middle.

this is really getting to me
 
Ok, according to your diagram, you have the data for the y-direction: [tex]T_{1y}+T_{2y}=mg[/tex]

How about the x direction?
 
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