A very weird capacitor association

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SUMMARY

The discussion focuses on calculating the equivalent capacitance in two capacitor associations, specifically configurations a) and b). The participants calculated capacitances for various combinations, including AB, AC, AD, BE, CE, DE in the first configuration, and EF, EH, FG, FI, FH, HI in the second. Feedback highlighted that only capacitances AB and DE were considered in the first configuration, and EF, FG, GH, HI in the second, raising questions about the exclusion of certain capacitances. The discussion emphasizes the importance of understanding charge distribution and surface charge density in capacitor calculations.

PREREQUISITES
  • Understanding of capacitor theory and definitions, specifically C=Q/U.
  • Familiarity with electric field concepts and potential difference.
  • Knowledge of surface charge density and its relation to electric fields, σ=ε0E.
  • Basic skills in circuit analysis and equivalent capacitance calculations.
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  • Research the principles of series and parallel capacitor configurations.
  • Learn about the impact of dielectric materials on capacitance.
  • Explore advanced capacitor network analysis techniques.
  • Study the effects of varying plate area and distance on capacitance values.
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Electrical engineers, physics students, and anyone involved in circuit design or capacitor analysis will benefit from this discussion.

jaumzaum
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In the capacitor association a) and b), calculate the equivalent capacitance
Given: area = A, vacuum permissivity = E, distance between each plate = d[PLAIN]http://img714.imageshack.us/img714/7073/semttulojznw.jpg In the first I've calculated the capacitance of AB, AC, AD, BE, CE, DE and added them. In the second the capacitance EF, EH, FG, FI, FH, HI and added

However the feedback only added AB and DE (in the first) and EF, FG, GH, HI in the second. Why have some capacitances been ignored?
 
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You can start from the definition of the capacitance: C=Q/U, charge on one plate divided by the potential difference between the plates. The potential difference is defined by the source, connected between points + and -. You need to determine the net charge on the plates connected together. The charge is distributed on the surfaces of the metal plates, and the surface charge density σ is equal to the electric field strength multiplied by the permittivity of vacuum: σ=ε0E where E=U/d.

ehild
 

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