What is the potential difference across the capacitor at time t=0?

  • Thread starter Thread starter WayneTie
  • Start date Start date
  • Tags Tags
    Electricity
Click For Summary
SUMMARY

The discussion focuses on calculating the potential difference across a capacitor at time t=0, analyzing current flow, and understanding the effects of adding a dielectric. Key concepts include the relationship between charge (Q), capacitance (C), and voltage (V) as described by the formula Q = CV. The discussion also addresses the behavior of electric fields in capacitors and the absence of current at the moment the switch is closed. The effects of resistive losses on potential energy are also highlighted.

PREREQUISITES
  • Understanding of capacitor fundamentals, including charge (Q) and voltage (V).
  • Familiarity with Ohm's Law (V = IR) and its application in circuits.
  • Knowledge of electric fields and their behavior in capacitors.
  • Concept of dielectrics and their impact on capacitance.
NEXT STEPS
  • Study the relationship between charge, capacitance, and voltage in capacitors using the formula Q = CV.
  • Learn about the effects of resistive elements in circuits and how they influence potential energy loss.
  • Investigate the role of dielectrics in capacitors and how they affect electric potential.
  • Explore the concept of electric fields in capacitors and the implications of current flow at different states.
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in understanding capacitor behavior in circuits and the effects of dielectrics on electric potential.

WayneTie
Messages
1
Reaction score
0
Hi, I don't get how to do this at all because I missed the lesson so could someone please help me? I appreciate it a lot!

First problem:

http://img55.imageshack.us/img55/9403/physics8tl.jpg

a) if the switch closes, what is i1? i1 is current at that position

b) graph v2 versus t graph

c) after a long time, if the switch opens, what is i2?

d) calculate Q (charge) of the capacitor

e) calculate U (potential energy) of the capacitor

Second problem:

There is a capacitor with two plates with very large surface area. They are set d distance apart and have equal but opposite charge densities.

a) diagram the current through the plates (no idea how to do this).

b) If a dielectric is added, does the electric potential increase, decrease, or stay the same? What mechanism causes this effect? (I think it goes down because of the q=cv formula but i don't know what mechanism).

Thanks a lot!
 
Last edited by a moderator:
Physics news on Phys.org
I honestly don't know how much you know and how much you don't know due to this 'missed lesson'. If you missed a lesson, you should get some sort of help or read up on your own. You would just be copying blindly otherwise.
 
Indicated current (I) flows from + side of battery, along the wires, to the - side of the battery. At a capacitor, the + charges accumulate on the + plate, and the E-field from them chases (the same number of) charges off the - plate.

As the current flows through a resistor, charges lose PE (friction-dominated), according to dV = I R .

Now, at time t=0, what is the potential difference across the capacitor?

question 2 part a : there is an E-field between the plates, but NO current.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
Replies
4
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
14
Views
3K
  • · Replies 30 ·
2
Replies
30
Views
3K