What is the potential difference across the capacitor at time t=0?

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Hi, I don't get how to do this at all because I missed the lesson so could someone please help me? I appreciate it a lot!

First problem:

http://img55.imageshack.us/img55/9403/physics8tl.jpg

a) if the switch closes, what is i1? i1 is current at that position

b) graph v2 versus t graph

c) after a long time, if the switch opens, what is i2?

d) calculate Q (charge) of the capacitor

e) calculate U (potential energy) of the capacitor

Second problem:

There is a capacitor with two plates with very large surface area. They are set d distance apart and have equal but opposite charge densities.

a) diagram the current through the plates (no idea how to do this).

b) If a dielectric is added, does the electric potential increase, decrease, or stay the same? What mechanism causes this effect? (I think it goes down because of the q=cv formula but i don't know what mechanism).

Thanks a lot!
 
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I honestly don't know how much you know and how much you don't know due to this 'missed lesson'. If you missed a lesson, you should get some sort of help or read up on your own. You would just be copying blindly otherwise.
 
Indicated current (I) flows from + side of battery, along the wires, to the - side of the battery. At a capacitor, the + charges accumulate on the + plate, and the E-field from them chases (the same number of) charges off the - plate.

As the current flows through a resistor, charges lose PE (friction-dominated), according to dV = I R .

Now, at time t=0, what is the potential difference across the capacitor?

question 2 part a : there is an E-field between the plates, but NO current.