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## Homework Statement

Based on my understanding of the question the diagram should be like this

ABC is an equilateral triangle with side 2a.Two circle are are drawn , with one of them crossing the points A,B and C.another circle crossess B and C with A as centre

Prove that the area enclosed by the two minor arcs BC are

(2a^2 / 9) x (3[itex]\sqrt{}3[/itex] - ∏)

## Homework Equations

Area of Segment of an Triangle

A= 1/2 a^2 (θ-sinθ)

## The Attempt at a Solution

Minor Arc Segment = Outer Segment - Inner Segment

Outer Segment

A=1/2 a^2 x (120 - sin120)

= (120-[itex]\sqrt{}3[/itex] / 2) a^2

Inner Segment

A=1/2 2a^2 x (60-sin60)

=(120-[itex]\sqrt{}3[/itex])a^2

Note:Update the working Steps in tmr ,sleep now! is 3am !

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