- #1
simplex
- 40
- 0
Let's say I have the equation p(t)f''(t)=Kf(t) with p(t) a known periodical function, K an unknown constant and f(t) the unknown function.
This is an eigenvalues problem that once solved gives a set of K={k1, k2,...} eigenvalues.
I get these eigenvalues and they coincide with the ones obtained by others so I got them right.
Question
What if I try to solve the equation with a K that does not belong to the set of eigenvalues?
I have the initial conditions: f(0) and f'(0), I choose a K which is not an eigenvalue and I try to solve numerically the equation (using MATLAB):
What happens with f(t)? It is clear that I will get a solution. What is the difference between this solution with a forbidden K and a solution with an allowed K?
This is an eigenvalues problem that once solved gives a set of K={k1, k2,...} eigenvalues.
I get these eigenvalues and they coincide with the ones obtained by others so I got them right.
Question
What if I try to solve the equation with a K that does not belong to the set of eigenvalues?
I have the initial conditions: f(0) and f'(0), I choose a K which is not an eigenvalue and I try to solve numerically the equation (using MATLAB):
What happens with f(t)? It is clear that I will get a solution. What is the difference between this solution with a forbidden K and a solution with an allowed K?