- #1

jwqwerty

- 43

- 0

(1/y-b)(dy/dt)=1

d(ln│y-b│)/dt=1

when i integrate both sides respect to t,

ln│y-b│=t+c (c is a constant)

y=±e^(at+c)+b

=±c1*e^at + b (c1 is a constant)

then the book replaces ±c1 with c2 (constant)

but isn't it wrong to do so? Because c2 can't show that it can have two answers.