About wavefunctions of Hydrogen atom

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
13 replies · 3K views
zhangpujumbo
Messages
18
Reaction score
0
Every one knows that wavefunctions are generally complex functions described by three quantum numbers n, l and m, and the number m is included in the form exp(i*m*fai). But here in the following webpage they are all real functions, I'm confused:confused: . Can anyone help me?

Thank u in advance!
 
Physics news on Phys.org
That page makes a mistake in listing (for example) the [itex]2p_x[/itex] and [itex]2p_y[/itex] wave functions as having m = 1 and -1. They are actually linear combinations of the functions with m = 1 and -1. Recall that

[tex]\cos \phi = \frac{e^{i \phi} + e^{-i \phi}}{2}[/tex]

[tex]\sin \phi = \frac{e^{i \phi} - e^{-i \phi}}{2i}[/tex]

If you measure [itex]L_z[/itex] for either of these functions, you get [itex]+ \hbar[/itex] half the time, and [itex]- \hbar[/itex] half the time, randomly.

The [itex]p_x[/itex] and [itex]p_y[/itex] functions are convenient for some purposes because they have lobes along the x and y axes, just like the [itex]p_z[/itex] (m = 0) function has lobes along the z axis.
 
Wave functions can be real; typically this is the case for bound states. (Strictly speaking this holds for the radial function.) Think about harmonic oscillator wave functions -- they are real. Pretty standard stuff.
Regards,
Reilly Atkinson
 
jtbell said:
That page makes a mistake in listing (for example) the [itex]2p_x[/itex] and [itex]2p_y[/itex] wave functions as having m = 1 and -1. They are actually linear combinations of the functions with m = 1 and -1. Recall that

[tex]\cos \phi = \frac{e^{i \phi} + e^{-i \phi}}{2}[/tex]

[tex]\sin \phi = \frac{e^{i \phi} - e^{-i \phi}}{2i}[/tex]

If you measure [itex]L_z[/itex] for either of these functions, you get [itex]+ \hbar[/itex] half the time, and [itex]- \hbar[/itex] half the time, randomly.

Yes.

jtbell said:
The [itex]p_x[/itex] and [itex]p_y[/itex] functions are convenient for some purposes because they have lobes along the x and y axes, just like the [itex]p_z[/itex] (m = 0) function has lobes along the z axis.

In Cartesean coordinates it's clearer:

[tex]p_z\ \ \propto\ \ \cos{\theta}\ =\ \frac{z}{r}[/tex]

[tex]p_x\ \ \propto\ \ \sin{\theta}\cos{\phi}\ =\ \frac{x}{r}[/tex]

[tex]p_y\ \ \propto\ \ \sin{\theta}\sin{\phi}\ =\ \frac{y}{r}[/tex]

They are all the same.Regards, Hans
 
Last edited:
jtbell said:
That page makes a mistake in listing (for example) the [itex]2p_x[/itex] and [itex]2p_y[/itex] wave functions as having m = 1 and -1. They are actually linear combinations of the functions with m = 1 and -1. Recall that

[tex]\cos \phi = \frac{e^{i \phi} + e^{-i \phi}}{2}[/tex]

[tex]\sin \phi = \frac{e^{i \phi} - e^{-i \phi}}{2i}[/tex]

If you measure [itex]L_z[/itex] for either of these functions, you get [itex]+ \hbar[/itex] half the time, and [itex]- \hbar[/itex] half the time, randomly.

The [itex]p_x[/itex] and [itex]p_y[/itex] functions are convenient for some purposes because they have lobes along the x and y axes, just like the [itex]p_z[/itex] (m = 0) function has lobes along the z axis.

Yes, I agree with your opinion very much!:approve:

There must be something wrong.

Thanks a lot:smile:
 
reilly said:
Wave functions can be real; typically this is the case for bound states. (Strictly speaking this holds for the radial function.) Think about harmonic oscillator wave functions -- they are real. Pretty standard stuff.
Regards,
Reilly Atkinson

I don't mean all wavefunctions must be complex.

But thank u all the same!
 
Hans de Vries said:
In Cartesean coordinates it's clearer:

[tex]p_z\ \ \propto\ \ \cos{\theta}\ =\ \frac{z}{r}[/tex]

[tex]p_x\ \ \propto\ \ \sin{\theta}\cos{\phi}\ =\ \frac{x}{r}[/tex]

[tex]p_y\ \ \propto\ \ \sin{\theta}\sin{\phi}\ =\ \frac{y}{r}[/tex]

en, it's clearer.
 
I don't know how to type mathematical equations here, it's too inconvenient.:cry:

How do you do that?
 
jtbell said:

It seems that all the equations are copied piece by piece, then typying equations will be too laborious a task

Is there a shortcut?
 
Not really. But LaTex is easy once you get past the initial shock.
 
inha said:
Not really. But LaTex is easy once you get past the initial shock.

I think a compact software like mathtype will help greatly.