Absorbance and Stray light helppp

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The discussion focuses on calculating stray light (Ps) as a percentage of incident light (Po) in a spectrophotometric analysis involving a weak acid, HA. Given the apparent absorbance (A(app)) of 0.047, a concentration of 2.00 x 10-6 M, and a cell length of 1 cm, the transmittance (T) was calculated to be 0.8974 using the formula A = -log T. The challenge arises from having two unknowns in the equation T = (P + Ps) / (Po + Ps), necessitating further clarification on the experimental setup and calculations to determine Ps accurately.

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atomicblast
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Hi, I've a chem assignment in which I've to calculate the stray light, Ps as a percentage of the incident light, Po.

Given the apparent absorbance A(app) 0.047, concentration of the solution 2.00 x 10pwr-6, cell length of 1cm, activity coefficients = 1.

I calculated the transmittance to be A = -log T , where T = 0.8974

T = P + Ps / Po + Ps = 0.8974
T = P / Po = 0.8974

I'm stuck after that with 2 unknowns in the equation. Could someone advice me on this?

Thanks a lot!
 
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It would help (yourself) a great deal if you could describe the experiment involved.
 
Okie, this is the question given:

The apparent absorbance of a solution of a weak acid, HA, was measured at different pH values (you may assume the pH meter was correctly calibrated, that activity coefficients are unity throughout, and that concentrations are reliable. A 1.00cm cell was used. None of the buffers used absorbs at the wavelength used. Results were as follows:

Concentration, M - 2.00 x 10pwr-6

Apparent Absorbance:
0.047 at pH 2,
0.045 at pH 4,
0.018 at pH 6,
0.010 at pH 8,
0.009 at pH 10

1) Calculate the stray light, Ps, as a percentage of the incident light, Po, in the spectrophotometer used.


Thanks again! :smile:
 

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