Abstract Algebra: Ring Proof (Multiplicative Inverse)

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SUMMARY

The discussion centers on proving that a commutative ring R, which contains a finite number of elements and has no zero divisors, is a field. The proof leverages the theorem stating that in a finite ring, every element is either a unit or a zero divisor. Since R has no zero divisors, all elements must be units, confirming that each has a multiplicative inverse. Thus, R satisfies the necessary conditions to be classified as a field.

PREREQUISITES
  • Understanding of commutative rings and their properties
  • Familiarity with the concept of units and zero divisors in ring theory
  • Knowledge of finite rings and their characteristics
  • Basic proof techniques in abstract algebra
NEXT STEPS
  • Study the properties of fields and their axioms in abstract algebra
  • Explore the implications of the theorem regarding finite rings and units
  • Learn about the structure and examples of commutative rings
  • Investigate the role of zero divisors in ring theory and their impact on ring classification
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Students of abstract algebra, mathematicians focusing on ring theory, and anyone interested in understanding the foundational concepts of fields and rings.

RJLiberator
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Homework Statement


Suppose R is a commutative ring with only a finite number of elements and no zero divisors. Show that R is a field.

Homework Equations



Unit is an element in R which has a multiplicative inverse. If s∈R with r*s = 1.
A zero divisor is an element r∈R such that there exists s∈R and rs = 0 (or sr = 0).

The Attempt at a Solution



1. Since R is a commutative ring, we only need to prove one axiom, that is that it satisfies the multiplicative inverse for all values in R.
2. I have a theorem that we just went over that states:
Theorem: If R is a finite ring, then for all r ∈ R, r is either a unit or a zero divisor.
3. Since the question states that there is no zero divisors in this finite ring, we can use the theorem to state that they must all be units.
4. Noting that they are all units means they all have the stipulation that x*s = 1. Meaning they all have a multiplicative inverse.

Proof is done.

Is this a complete proof?
 
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RJLiberator said:

Homework Statement


Suppose R is a commutative ring with only a finite number of elements and no zero divisors. Show that R is a field.

Homework Equations



Unit is an element in R which has a multiplicative inverse. If s∈R with r*s = 1.
A zero divisor is an element r∈R such that there exists s∈R and rs = 0 (or sr = 0).

The Attempt at a Solution



1. Since R is a commutative ring, we only need to prove one axiom, that is that it satisfies the multiplicative inverse for all values in R.
2. I have a theorem that we just went over that states:
Theorem: If R is a finite ring, then for all r ∈ R, r is either a unit or a zero divisor.
3. Since the question states that there is no zero divisors in this finite ring, we can use the theorem to state that they must all be units.
4. Noting that they are all units means they all have the stipulation that x*s = 1. Meaning they all have a multiplicative inverse.

Proof is done.

Is this a complete proof?
Yes. If I were in a pedantic mood, I could remark that you should exclude 0 in some statements.
 
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