Acceleration and speed as m*s^-1

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Homework Help Overview

The discussion revolves around understanding the units of acceleration and speed, specifically the notation involving negative powers, in the context of a physics problem involving motion under constant acceleration.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses confusion regarding the notation of units such as m/s^-2 and m/s^-1, questioning their meaning and validity. Some participants clarify that these are standard algebraic manipulations of units, explaining how negative powers relate to fractions.

Discussion Status

Participants are actively engaging in clarifying the notation of units, with some providing mathematical explanations. The original poster acknowledges the clarification, indicating a productive exchange of ideas.

Contextual Notes

The original poster is working within the constraints of a homework problem that involves calculating time, retardation, and distance traveled under specific conditions of motion.

Xecutive
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I was given this question today and I have never seen acceleration or speed with a minus power in the unit (m/s^-2). Also speed in the question has a ^-1 in the unit and I thought the unit for speed was m/s (meters per second)

Homework Statement



A body starts from rest and is subject to a constant contant acceleration of 4ms^-2 up to a speed of 20ms^-1. It then travels 20ms^-1 for 30 seconds after witch time it is retarded to a speed of 4ms^-1, if the complete motion takes 50 seconds, Find:

A) The time taken to reach 20ms^-1.

B) The retardation.

C)Total distance travelled.

Homework Equations


The Attempt at a Solution



I have know idea what these strange units mean.
 
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Hi Xecutive. Welcome to PF!

It is simply standard algebra applied to units (which should be treated as mathematical objects).

$$x^{-1} = \frac{1}{x}$$

$$\mathrm{m} \; \mathrm{s}^{-1} = \frac{\mathrm{m}}{\mathrm{s}}$$

$$\mathrm{m} \; \mathrm{s}^{-2} = \frac{\mathrm{m}}{\mathrm{s}^2}$$

Note that it is not ##\mathrm{m} / \mathrm{s}^{-1}##, but ##\mathrm{m} \; \mathrm{s}^{-1}##. The former would give
$$
\mathrm{m} / \mathrm{s}^{-1} = \frac{\mathrm{m}}{\mathrm{s}^{-1}} = \mathrm{m} \; \mathrm{s}
$$
 
Xecutive said:
I was given this question today and I have never seen acceleration or speed with a minus power in the unit (m/s^-2).
you mean ms^-2 not m/s^-2
Also speed in the question has a ^-1 in the unit and I thought the unit for speed was m/s (meters per second)
yes, the unit for speed is m/s, and m/s can be written as ms^-1...it's just taking the denominator, s, and placing it in the numerator as s^-1.
I personally would rather see it written as m/s instead of ms^-1, but they are nevertheless mathematically the same unit, just an algebraic manipulation of the variables.

Welcome to these forums!
 
It seems so obvious now.

Thanks.
 

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