1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Acceleration as a Function of Velocity

  1. Feb 8, 2010 #1
    1. The problem statement, all variables and given/known data

    When 2<=t<=6
    v= 4/a in ft/sec2

    v= 6 ft/sec @ t=2s

    Find a at t=3s

    2. Relevant equations


    3. The attempt at a solution

    My integration is horribly wrong and honestly not worth typing. LOL
  2. jcsd
  3. Feb 8, 2010 #2
    You write,

    v= 4/a in ft/sec^2

    something is goofy here, something is not right?
  4. Feb 8, 2010 #3
    I'm sorry....acceleration (a) should be in ft/sec^2

    so a=4v^-1
  5. Feb 8, 2010 #4
    Now you have acceleration = 4/velocity what are the units of the 4

    acceleration * time has units of velocity. Your expression a=4v^-1 still confuses me. Does the number 4 have units? I'm missing something that others might be missing as well.
  6. Feb 8, 2010 #5
    No units on 4 it's just a constant?

    the original problem is v = 4 divided by acceleration or v = 4/a

    I solved for acceleration (a hint by my professor) so acceleration = 4 divided by velocity or a = 4/v
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook