Acceleration as a Function of Velocity

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Homework Help Overview

The discussion revolves around a problem involving acceleration as a function of velocity, specifically examining the relationship between velocity and acceleration over a defined time interval. The original poster presents a scenario where velocity is expressed as a function of acceleration, leading to confusion regarding the units and the formulation of the equations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between acceleration and velocity, questioning the correctness of the original equation provided. There is an attempt to clarify the units associated with the constant in the equation and the implications of the formulation.

Discussion Status

The discussion is ongoing, with participants raising questions about the units of the constant in the equation and the validity of the expressions used. Some guidance has been offered regarding the relationship between acceleration and velocity, but no consensus has been reached on the correct interpretation of the problem.

Contextual Notes

Participants note potential confusion stemming from the original problem statement and the definitions of the variables involved. There is an acknowledgment of the need for clarity regarding the units of measurement and the implications of the equations presented.

DeboPGH
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Homework Statement



When 2<=t<=6
v= 4/a in ft/sec2

v= 6 ft/sec @ t=2s

Find a at t=3s


Homework Equations



a=dv/dt.

The Attempt at a Solution



My integration is horribly wrong and honestly not worth typing. LOL
 
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DeboPGH said:

Homework Statement



When 2<=t<=6
v= 4/a in ft/sec2

v= 6 ft/sec @ t=2s

Find a at t=3s


Homework Equations



a=dv/dt.

The Attempt at a Solution



My integration is horribly wrong and honestly not worth typing. LOL

You write,

v= 4/a in ft/sec^2

something is goofy here, something is not right?
 
Spinnor said:
You write,

v= 4/a in ft/sec^2

something is goofy here, something is not right?

I'm sorry...acceleration (a) should be in ft/sec^2

so a=4v^-1
 
Now you have acceleration = 4/velocity what are the units of the 4

acceleration * time has units of velocity. Your expression a=4v^-1 still confuses me. Does the number 4 have units? I'm missing something that others might be missing as well.
 
Spinnor said:
Now you have acceleration = 4/velocity what are the units of the 4

acceleration * time has units of velocity. Your expression a=4v^-1 still confuses me. Does the number 4 have units? I'm missing something that others might be missing as well.

No units on 4 it's just a constant?

the original problem is v = 4 divided by acceleration or v = 4/a

I solved for acceleration (a hint by my professor) so acceleration = 4 divided by velocity or a = 4/v
 

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