# Acceleration as a Function of Velocity

1. Feb 8, 2010

### DeboPGH

1. The problem statement, all variables and given/known data

When 2<=t<=6
v= 4/a in ft/sec2

v= 6 ft/sec @ t=2s

Find a at t=3s

2. Relevant equations

a=dv/dt.

3. The attempt at a solution

My integration is horribly wrong and honestly not worth typing. LOL

2. Feb 8, 2010

### Spinnor

You write,

v= 4/a in ft/sec^2

something is goofy here, something is not right?

3. Feb 8, 2010

### DeboPGH

I'm sorry....acceleration (a) should be in ft/sec^2

so a=4v^-1

4. Feb 8, 2010

### Spinnor

Now you have acceleration = 4/velocity what are the units of the 4

acceleration * time has units of velocity. Your expression a=4v^-1 still confuses me. Does the number 4 have units? I'm missing something that others might be missing as well.

5. Feb 8, 2010

### DeboPGH

No units on 4 it's just a constant?

the original problem is v = 4 divided by acceleration or v = 4/a

I solved for acceleration (a hint by my professor) so acceleration = 4 divided by velocity or a = 4/v