- #1

jenny121

- 2

- 3

- Homework Statement
- The distance moved by a mass is related to the time by x=3e^(0.4t) m. Find the following value after 5 sec

- Relevant Equations
- x=3e^(0.4t)

Distance:

substitute t=5 into x=3e^(0.4t)

22.17m

Velocity:

v=dx/dt

=1.2e^0.4t____(1)

Sub t=5 back into (1)

v= 8.867m/s

Acceleration:

a=dV/dt

=0.48e^0.4t____(2)

sub t=5 back into (2)

a= 3.547 m2/s

I am not sure if i am doing this right on dx/dt and dv/dt

substitute t=5 into x=3e^(0.4t)

22.17m

Velocity:

v=dx/dt

=1.2e^0.4t____(1)

Sub t=5 back into (1)

v= 8.867m/s

Acceleration:

a=dV/dt

=0.48e^0.4t____(2)

sub t=5 back into (2)

a= 3.547 m2/s

I am not sure if i am doing this right on dx/dt and dv/dt