Acceleration due to gravity help

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SUMMARY

The discussion focuses on calculating the time it takes for a 1kg mass to fall 2 meters on the moon, utilizing the gravitational constant and the moon's mass and radius. The calculated acceleration due to gravity on the moon is approximately 1.58 m/s², although it is noted that the accepted value is around 1.62 m/s². To determine the time of fall, the formula x = v₀t + ½at² is recommended, where 'a' represents the acceleration due to gravity. The gravitational constant G is used to derive the acceleration, confirming its relevance in the calculations.

PREREQUISITES
  • Understanding of Newton's Universal Law of Gravitation
  • Familiarity with kinematic equations, specifically x = v₀t + ½at²
  • Knowledge of gravitational constant (G = 6.673 x 10^-11 Nm²/kg²)
  • Basic concepts of mass and radius in gravitational calculations
NEXT STEPS
  • Research the derivation of gravitational acceleration on celestial bodies
  • Learn about kinematic equations and their applications in physics
  • Explore Newton's Second Law of Motion and its implications in gravitational contexts
  • Investigate the differences in gravitational acceleration on various celestial bodies
USEFUL FOR

Students studying physics, educators teaching gravitational concepts, and anyone interested in the mechanics of falling objects in different gravitational fields.

sheevz
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acceleration due to gravity help!

Homework Statement



PROB: How long would it take for a mass of 1kg to fall a distance of 2m to the surface of the moon?

Homework Equations



G=6.673*10^-11 Nm^2/kg^2
R of moon = 1.76*10^6m
m of moon = 7.35*10^22kg

The Attempt at a Solution


i started by finding the acceleration due to gravity by using g= (m)(G)/r^2
(m=mass of moon, G as the gravitational constant, r= radius of moon)
finding that g is 1.58m/s^2
now i am lost in what formula to use to get the displacement of this object?
 
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Check your acceleration due to gravity for the moon, it should be ~1.62m/s^2

To solve for time t, use the formula x=v_{0}t+\frac{1}{2}at^2
 
ok i don't know if this is a type o or not but yes the acceleration due to gravity for the moon is ~1.62m/s^2 but in this prob, the radius is given @ 1.76*10^6 thus giving an acceleration due to gravity @ ~1.58m/s^2
and in using the above formula you gave me, X=volt+.5at^2
is Vo my accel due to gravity on the moon and a my G constant? why in the original problem was G given to me, is it necessary in this? (probably a stupid question)
 
Those pieces of data were given to you so you could work out the acceleration due to gravity, to sub into the formula konthelion gave to you. Obviously you did this through Newtons Universal Law of Gravitation. After we have the force, Using Newtons Second Law we can have the acceleration. We can take the Force and acceleration to be practically constant, because the change in the value of r in the Universal Gravitation Law changes by one 1m, very small in comparison to the radius of the moon. Although yes, it is true it is not exactly constant.
 

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