Acceleration due to Gravity on Mars

In summary, the conversation discusses the successful landing of two Martian probes in 2004 and the use of telemetry to determine the acceleration due to gravity near the Martian surface. The solution involved using equations for projectile motion to calculate the time and peak height of the probe's bounce, and then using this information to find the acceleration due to gravity. The conversation also suggests remembering the general formulae for projectile motion for future use.
  • #1
mlee16
2
0

Homework Statement


Question: In 2004 two Martian probes successfully landed on the Red Planet. The final phase of the landing involved bouncing the probes until they came to rest (they were surrounded by protective inflated "balloons"). During one of the bounces, the telemetry (electronic data sent back to Earth) indicated that the probe took off at 25.0 m/s at an angle of 20 degrees and landed 110 m away (and then bounced again). Assuming the landing region was level, determine the acceleration due to gravity near the Martian surface.

Homework Equations


delta x = .5 * (velocity final + velocity initial) * time
Y final = y initial + .5 (velocity final + velocity initial) * time
Y final = y initial + (velocity initial) * time - .5 (acceleration) (time)^2

The Attempt at a Solution



delta x = .5 * (velocity final + velocity initial) * time
110 m = .5 * (25 cos 20 deg + 25 cos 20 deg) * time
Time = 4.68 s

I then found the height at the maximum point
Y final = y initial + .5 (velocity final + velocity initial) * time
Y final = 0 m + .5 (0 m/s + 25 sin 20 deg) * 4.68 sec
Y final = 20 m

I then used this equation to find acceleration
Y final = y initial + (velocity initial) * time - .5 (acceleration) (time)^2
20 = 0 m + (25 sin 20)(4.68) - .5(acceleration)(4.68)^2
Acceleration = 1.827 m/sec^2
 
Physics news on Phys.org
  • #2
Solution looks good. Doesn't it match with the answer?
 
  • #3
No haha I actually just figured it out. I should have halved my time when using the second equation because you're calculating the peak height.
 
  • #4
The equatins you used are not generally used. But they are correct. I would suggest you remember the formulaes of projectile motion. You can derive it if you want. There are general formulaes for maximum height, range and time of flight!
 
  • #5
The acceleration due to gravity near the Martian surface, as determined by the data from the probe's landing, is approximately 1.827 m/s^2. This value is significantly lower than the acceleration due to gravity on Earth, which is 9.8 m/s^2. This is because Mars has a smaller mass and a lower surface gravity compared to Earth. The successful landing of the probes on Mars is a testament to the accuracy and effectiveness of scientific methods and calculations. Further studies and experiments on Mars will continue to provide valuable insights and understanding of the Red Planet's unique environment and conditions.
 

1. What is the value of acceleration due to gravity on Mars?

The value of acceleration due to gravity on Mars is approximately 3.711 m/s². This is about 38% of the value on Earth, which is 9.8 m/s².

2. How does the acceleration due to gravity on Mars compare to that of Earth?

The acceleration due to gravity on Mars is about 38% of the value on Earth. This means that objects will fall slower and have less weight on Mars compared to Earth.

3. What factors affect the acceleration due to gravity on Mars?

The acceleration due to gravity on Mars is affected by the mass and radius of the planet. As Mars has less mass and a smaller radius than Earth, its gravity is weaker.

4. How was the acceleration due to gravity on Mars determined?

The acceleration due to gravity on Mars was determined using data collected by various spacecrafts, such as the Mars Global Surveyor and the Mars Reconnaissance Orbiter. These spacecrafts measured the gravitational pull of Mars on their orbits to calculate the acceleration due to gravity.

5. Can the acceleration due to gravity on Mars change over time?

Yes, the acceleration due to gravity on Mars can change over time. This is due to various factors such as tectonic activity, volcanic eruptions, and the redistribution of mass on the planet's surface. However, these changes are very small and have a minimal impact on the overall value of acceleration due to gravity on Mars.

Similar threads

  • Introductory Physics Homework Help
Replies
7
Views
971
  • Introductory Physics Homework Help
Replies
1
Views
726
  • Introductory Physics Homework Help
Replies
3
Views
783
  • Introductory Physics Homework Help
Replies
17
Views
819
  • Introductory Physics Homework Help
Replies
11
Views
949
  • Introductory Physics Homework Help
Replies
6
Views
890
Replies
11
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
158
  • Introductory Physics Homework Help
Replies
6
Views
961
  • Introductory Physics Homework Help
Replies
13
Views
2K
Back
Top