1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Acceleration in Harmonic Motion

  1. Jun 3, 2017 #1
    Problem:
    A pendulum that has a period of 3.00000s and that is located where the accleration due to gravity is 9.79 m/s^2 is moved to a location where the acceleration due to gravity is 9.82 m/s^2. What is its new period, in s?

    Equations
    Equation for Harmonic motion: x = A sin (2pi * f * t)

    Acceleration for Harmonic motion: a = -4pi^2 A f^2 sin(2pi f t)

    f = 1/t = 1/3

    Attempt:
    Let A = 4 for both problems.
    9.79 = 16/9 * pi^2 * sin (2pi/3 t)

    Solving for t,
    sin(2pi/3 * t) = 0.55796309317
    2pi/3 * t = 0.5919292673 (radians)
    t = 0.282654065 seconds

    9.82 = 16 * pi^2 * f^2 sin(2pi * 0.282654 * f)
    f^2 sin(2pi * 0.282654 * f) = 0.06218587646

    Now I get a lot of answers for f.
    https://www.wolframalpha.com/input/?i=x^2+sin(2pi+*+0.282654+*+x)+=+0.06218587646

    Not sure which one is the answer.

    Thank you!
     
  2. jcsd
  3. Jun 3, 2017 #2

    SammyS

    User Avatar
    Staff Emeritus
    Science Advisor
    Homework Helper
    Gold Member

    Hello ciao_potter . Welcome to PF !

    You are not to use the acceleration resulting from harmonic motion.
    The pendulum is not likely to have an acceleration of g .

    What is the formula for the period of simple pendulum?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Acceleration in Harmonic Motion
Loading...