Problem: A pendulum that has a period of 3.00000s and that is located where the accleration due to gravity is 9.79 m/s^2 is moved to a location where the acceleration due to gravity is 9.82 m/s^2. What is its new period, in s? Equations Equation for Harmonic motion: x = A sin (2pi * f * t) Acceleration for Harmonic motion: a = -4pi^2 A f^2 sin(2pi f t) f = 1/t = 1/3 Attempt: Let A = 4 for both problems. 9.79 = 16/9 * pi^2 * sin (2pi/3 t) Solving for t, sin(2pi/3 * t) = 0.55796309317 2pi/3 * t = 0.5919292673 (radians) t = 0.282654065 seconds 9.82 = 16 * pi^2 * f^2 sin(2pi * 0.282654 * f) f^2 sin(2pi * 0.282654 * f) = 0.06218587646 Now I get a lot of answers for f. https://www.wolframalpha.com/input/?i=x^2+sin(2pi+*+0.282654+*+x)+=+0.06218587646 Not sure which one is the answer. Thank you!