Calculate the harmonic motion equation for the following case
A=0.1m, t=0s x=0.05m, v(t=0)>0 a(t=0)= -0.8m/s^2
x(t)= +/-Acos/sin ( (2pi/T)/*t)
The Attempt at a Solution
A is given to be 0.1 so I simply place it into the equation. Now I have to decide whether the graph is sin or cos and the sign. Since the velocity is positive at t=0, the sign must be +. I am confused about whether it is sin or cos because the graph when I sketch it looks like a kind of transformation starting from t=0 x=0.05m and going upwards. I am also not sure about how to find T. is there an equation I am missing?