Acceleration in Two Dimensions of watercraft

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chudzoik
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Homework Statement


A watercraft with an initial velocity of 6.4 m/s [E] undergoes an average acceleration of 2.0 m/s2 for 2.5 s. What is the final velocity of the watercraft?

Homework Equations


vf = vi + a * t
a = v / t
v = v2 + (-v1)
pythagoras and cosine law?

The Attempt at a Solution



I think I need to separate the velocities into x and y components and calculate the final velocity in both the x and y components to find the final velocity, but I don't know if that's correct. To be honest I don't really know where how to start the question.
 
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chudzoik said:
I think I need to separate the variables into x and y components and calculate the final velocity in both the x and y components to find the final velocity, but I don't know if that's correct.
Yep, that's how you should do it. You've got the x acceleration and y acceleration, and so you can solve the equations of motion for each coordinate separately.
 
But I don't think I have enough known variables to do that. If I use vfx = vix + ax * t then I don't have ax and I don't have the initial velocity in the y direction either so I can't figure out the final velocity in the y direction.
 
Yes, you do have ax, because the question says that the acceleration is only in the south direction.
And you do know the initial velocity in the y direction, because the question says that the initial velocity is purely to the east.
 
So they are both 0 then? I think that clears up a lot of my confusion with this problem.