Acceleration is (-2.0i + 4.0j), velocity is 12 m/s

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SUMMARY

The discussion centers on a physics problem involving a particle moving in the xy-plane with an initial velocity of 12 m/s in the positive x-direction and a constant acceleration of (-2.0i + 4.0j) m/s². The objective is to determine the x-coordinate of the particle when its y-coordinate reaches 18 m. Key equations utilized include the kinematic equation rf = ri + vit + 1/2at² and the relationships between acceleration, velocity, and position. Participants explore integration techniques to derive velocity as a function of time and subsequently apply these to find the required x-coordinate.

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Homework Statement



At T=0 a particle leaves the origin with a velocity of 12 m/s in the positive x direction and moves in the xy plane with a constant acceleration of (-2.0i + 4.0j)m/s^2. At the instant the y coordinate of the particle is 18 m, what is the x coordinate of the particle.

Homework Equations



rf=ri + vit + 1/2at2
=(12m/s)(t) + 1/2 (-2.0i + 4.0j)t2

So stuck. Any direction or help would be greatly appreciated!
 
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so you know initial velocity to be 12.0i..
now you also know a = dv/dt
and v = dr/dt (r being position)..

Which mathematical (or calculus) tool can you use to get your answer now? and how?
 
Okay, so I am going to play with these equations and try to get closer...

a = dv/dt
(-2.0i + 4.0j)= 12i / dt

dt = 12i / -6.0i + 4.0j
dt = -6.0i - 4.0 j

v = dr/dt
12 i = xi - 18j / -6.0i - 4.0j
12i(-6.0i - 4.0 j) = xi - 18j

oh dear, now I am stuck again and I am not even sure I have done this part correctly.
 
new^2^physics said:
Okay, so I am going to play with these equations and try to get closer...

a = dv/dt
(-2.0i + 4.0j)= 12i / dt


that isn't correct...

a=dv/dt
(-2.0i+4.0j)dt=dv
integrating

-(2t)i + (4t)j = v-12

so you get v as a function of time... now proceed in a similar manner...
 
new^2^physics said:
At T=0 a particle leaves the origin with a velocity of 12 m/s in the positive x direction...

So, what are V_{ix}[/tex] and V_{iy}[/tex]?
 

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