Two Dimensional Kinematics probelms

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Homework Help Overview

The discussion revolves around two-dimensional kinematics problems involving particles moving in the xy plane with given initial velocities and constant accelerations. Participants are analyzing the motion of the particles to determine their speeds and positions at specific instances.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants are attempting to apply kinematic equations to solve for time and final velocities. There are questions about the correctness of initial calculations and the need for separate equations for x and y components of motion. Some participants express confusion regarding the information provided and how to proceed without certain values.

Discussion Status

There is an ongoing exploration of the problems, with some participants questioning their approaches and calculations. Guidance has been offered regarding the separation of x and y components, but no consensus or resolution has been reached yet.

Contextual Notes

Participants note potential missing information, particularly regarding the direction of initial velocities and the implications of mixed quantities in their equations. There is an emphasis on ensuring clarity in the setup of the problems.

riken9
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Homework Statement



1. At t = 0, a particle leaves the origin with a velocity of 9.0 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (2.0i - 4.0j) m/s2. At the instant the x coordinate of the particle is 15 m, what is the speed of the particle?

2. A particle starts from the origin at t = 0 with a velocity of 6.0 m/s and moves in the xy plane with a constant acceleration of (-2.0 + 4.0 ) m/s2. At the instant the particle achieves its maximum positive x coordinate, how far is it from the origin?


Homework Equations



rf = ri + vt + 1/2at^2
vf = vi + at

The Attempt at a Solution


1. rf = ri + vt + 1/2at^2
t = 2.25 [seconds]

vf = (9j) + [2i - 4j)t

Sub t into there and i get 4 m/s But the answer is: 10 m/s


2. v(initial)=6i m/s
v(final)=?
a= (-2i + 4j) m/s^2
starts at coordinate (0,0)
need to find max x point

rf = 6i + [-1i + 2j]t^2

vf = vi + at
How do i find t if i don't have final velocity? Answer is: 20m.
 
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Hello, riken9. Welcome to PF!

For the first problem, your answer for the time is incorrect. Can you show your work so we can find the mistake?

For the second problem, there is not enough information given. Did they give you the direction of the velocity at t = 0? [EDIT: OK, it looks like from your work that the initial velocity is in the x direction. I think you will find things will be easier if you write out separate equations for the x and y components of the motion.]
 
for the first question rf = ri + vt + 1/2at^2, i did 15 = 0 + 9t - 2t^2 and got 2.25 seconds. I also tried 15 = 9j + [i - 2j]t^2 and got 1.27 seconds, which is also wrong.

And for the second problem i tried that still couldn't get it right.
 
riken9 said:
for the first question rf = ri + vt + 1/2at^2, i did 15 = 0 + 9t - 2t^2

In the above equation you have mixed together x quantities (blue) and y quantities (red). Instead, write out equations for just the x component of motion and separate equations for the y component of motion. For example

x = xi + vxit + (1/2)axt2

y = yi + vyit + (1/2)ayt2

or for velocity,

vx = vxi + axt

vy = vyi + ayt

So, try using x = xi + vxit + (1/2)axt2 to find the time for the first problem.
 
Last edited:

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