Acceleration of a block on a massive pulley

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SUMMARY

The discussion centers on calculating the acceleration of a block hanging from a string wrapped around a hollow pulley. The block has a mass of 0.7 kg, while the hollow pulley has a mass of 1.3 kg and a radius of 0.4 m. The correct formula for acceleration is a = -g(m1)/(m1 + 0.5*mp), where g is the acceleration due to gravity. The calculated acceleration is approximately -5.081 m/s², indicating the block's downward acceleration under gravity's influence.

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  • Understanding of Newton's laws of motion
  • Familiarity with rotational dynamics and moment of inertia
  • Knowledge of gravitational acceleration (g = 9.8 m/s²)
  • Ability to manipulate algebraic equations
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  • Study the moment of inertia for hollow cylinders
  • Learn about the dynamics of non-uniform pulleys
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EchoTheCat
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Homework Statement


A block of mass MB = 0.7 kg hangs from a string wrapped around a hoop that can rotate around its center. The hoop has a mass of MH = 1.3 kg and a radius of R = 0.4 m. The block descends under the influence of gravity. What is the magnitude of the acceleration of the mass in m/s2?

Homework Equations


a = -g(m1-m2)/(m1+m2+.5mp)
where, m1 and m1 = masses of the blocks and mp = mass of the pulley

The Attempt at a Solution


a = -9.8*(0.7)/(.7+.5*1.3) = -5.081 m/s/s
 
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EchoTheCat said:

Homework Statement


A block of mass MB = 0.7 kg hangs from a string wrapped around a hoop that can rotate around its center. The hoop has a mass of MH = 1.3 kg and a radius of R = 0.4 m. The block descends under the influence of gravity. What is the magnitude of the acceleration of the mass in m/s2?

Homework Equations


a = -g(m1-m2)/(m1+m2+.5mp)
where, m1 and m1 = masses of the blocks and mp = mass of the pulley
The equation you quote appears to assume a pulley which is a solid disk or cylinder with two masses hanging, one from either side. That's not the problem at hand. This pulley is hollow. There is a mass hanging from only one side.
 

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