Accleration problem - car strikes a tree

Click For Summary
SUMMARY

A car traveling at 25 m/s strikes a tree, causing the driver to decelerate over a distance of 0.72 m. The average acceleration of the driver during the collision was calculated using the equation: final velocity² = initial velocity² + 2 * acceleration * change in distance. The correct calculation reveals an average acceleration of approximately -44.4 m/s², which translates to about -4.54 g's, indicating a significant deceleration experienced by the driver.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Familiarity with the concept of acceleration and its units
  • Knowledge of converting acceleration to g's (gravitational units)
  • Basic algebra skills for solving equations
NEXT STEPS
  • Study kinematic equations in detail, focusing on their applications in collision scenarios
  • Learn how to convert between different units of acceleration, particularly to g's
  • Explore real-world applications of deceleration in automotive safety
  • Investigate the physics of collisions and energy transfer during impacts
USEFUL FOR

Physics students, automotive engineers, safety analysts, and anyone interested in understanding the dynamics of vehicle collisions and the forces involved.

Frosty8
Messages
2
Reaction score
0

Homework Statement



A car traveling at 25m/s strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.72 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's," where 1.00g = 9.80 m/s2



Homework Equations



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)




The Attempt at a Solution



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)
o^2=25^2+2a(.72)
so for the acceleration i got -15ms^2/9.8ms^2= -1.53ms^2 and this was wrong. what did i do wrong?
 
Physics news on Phys.org


Welcome, Frosty8, to the Physics Forums!
Frosty8 said:

Homework Statement



A car traveling at 25m/s strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.72 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's," where 1.00g = 9.80 m/s2



Homework Equations



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)




The Attempt at a Solution



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)
o^2=25^2+2a(.72)
yes, correct
so for the acceleration i got -15ms^2/9.8ms^2= -1.53ms^2 and this was wrong. what did i do wrong?
math error: 625 = -1.44a, theerfore, a = -434 m/s^2 , which is how many 'g's'?
 


Thank you
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
1K
Replies
4
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
  • · Replies 3 ·
Replies
3
Views
932
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K