Accumulation Points: Set with Two or Countably Infinite?

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The discussion centers on the existence of sets with a specific number of accumulation points. Participants explore the possibility of having exactly two distinct accumulation points, suggesting the set {1/n + (-1)^n} as an example. There is also inquiry into whether a set can have countably infinite accumulation points, with hints provided for constructing such a set using natural numbers. One suggested approach involves creating a set that converges to a limit as one variable approaches infinity. The conversation concludes with a participant expressing understanding of the concepts discussed.
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Homework Statement


is there are a set with countably infinite number of accumulation points?


Homework Equations



is there a set with exactly two distinct accumulation points?

The Attempt at a Solution


a set with two accumulation points might be: {1/n + (-1)^n}
i have no clue about the countably infinite one

hope someone could help!

thx a lot
 
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nitro said:

Homework Statement


is there are a set with countably infinite number of accumulation points?


Homework Equations



is there a set with exactly two distinct accumulation points?

The Attempt at a Solution


a set with two accumulation points might be: {1/n + (-1)^n}
i have no clue about the countably infinite one
Your idea is fine, but be sure to write it correctly (with an ": n in N").

I'd prefer not to spoon feed you an example for the other; rather, consider perhaps a set (in R) that depends on two natural numbers. Say, \{y_n, y_n + x_m: n, m \in \mathbb{N}\}, which you might construct so that \lim_{m\to\infty} x_m = 0 and so, for each fixed n, \lim_{m\to\infty} y_n+x_m=y_n.
 
Last edited:
aahaaaaaaa! :)
thx a lot, i got it
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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