Adding Vectors: How to Find the Resultant with 3 Given Force Vectors

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Homework Help Overview

The discussion revolves around the addition of three force vectors to determine the resultant vector. The vectors have specified magnitudes and angles, with one vector aligned along the positive y-axis. Participants are exploring methods to combine these vectors effectively.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss breaking down the vectors into their x and y components as a method for addition. Some express a desire for a quicker method, questioning whether there is a more efficient way to find the resultant without component breakdown.

Discussion Status

There is ongoing exploration of how to combine the components after they have been calculated. Participants have provided guidance on using trigonometric functions and the process of recombining components to find the magnitude and direction of the resultant vector.

Contextual Notes

Participants mention that the forces are derived from point charges, indicating that gravitational effects are not a factor in this scenario. There is also a focus on ensuring clarity in the calculations of the components and resultant vector.

suki86
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Need help adding vectors --please help

Homework Statement


i have 3 force vectors i want to add to get the resultant.
vector a mag=1.31N and is 51.34deg to the x-axis (Quad 1)
vector b mag= 1.31N and is 51.34deg to the x-axis (Quad 4)
vector c mag = .719N and is along the pos y axis

how do you add these for resultant?
ive learned this before but forgot how to add them, --isnt there a simple way to get the one resultant vector?
thanks for any help!



Homework Equations





The Attempt at a Solution

 
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also, the forces are from point charges, so no gravity
 
Split them all into x and y components and then add the components to get the components of the sum.
 
thanks for the reply.

ok but isn't there a faster way to get the resultant rather than breaking them apart then putting back together again?
 
Fxa = 1.31N * cos 51.34deg = .818353N
Fxb = 1.31N * cos 51.34deg = .818353N
Fxc...... = 0 (because force is along the y-axis)

Fya = 1.31N * sin 51.34deg = 1.0229N
Fyb = 1.31 * sin51.34deg = 1.0229N
Fyc = .719N = .719N (because along the y-axis)
 
ok so, I broke them down into x and y components. just need help adding them now?
thanks!
 
I'm pretty sure you have to use basic trig functions to find the lengths. Then, add them together.
 
Ok, so now add all of the x's and all of the y's. That gives you the x and y components of the total force T. Do you need to get the total magnitude and direction of T? Do you know how to do that?
 
yeah total magnitude is what i want.
So Fx = 1.636706
Fy = 2.7648

ho do i add them? thanks
 
  • #10
Good so far. You don't 'add' them. The vector is (Fx,Fy). The magnitude is sqrt(Fx^2+Fy^2), the angle is arctan(Fy/Fx). It's the opposite of splitting into components, you are 'recombining' the components.
 
  • #11
oh duh. this is just pythagarus isn't it? i mean x and y components mean i just get the hypotenuse and that's how you "add" them right>?
so, sq rt Fx^2 + Fy^2 = resultant vector
 
  • #12
i mean the MAGNITUDE of the vector at least.
 
  • #13
Yes. You are on the right track.
 

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