Adding Vectors in Physics 1 to get the Net Displacement

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SUMMARY

The discussion focuses on calculating the net displacement of a car driven in multiple directions: 43 km east, 29 km north, and 24 km at an angle of 29° east of north. The user calculated a total displacement of approximately 75.80 km and an angle of 32.42° north of east, which were incorrect. The correct answers are 74.05 km for the magnitude and 42.46° north of east for the angle. The discrepancy in the angle calculation is highlighted as the primary issue needing resolution.

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  • Vector addition in physics
  • Trigonometric functions (sine, cosine)
  • Understanding of displacement and direction
  • Basic geometry involving angles
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  • Study trigonometric functions for angle calculations
  • Practice problems involving displacement and direction
  • Learn how to resolve vectors into components
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Students studying physics, particularly those focusing on vector analysis and displacement calculations, as well as educators seeking to clarify vector addition concepts.

Wm_Davies
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Homework Statement



A car is driven east for a distance of 43 km, then north for 29 km, and then in a direction 29° east of north for 24 km. Determine (a) the magnitude (in km) of the car's total displacement from its starting point and (b) the angle (from east) of the car's total displacement measured from its starting direction.


The Attempt at a Solution



I do not know where I am going wrong, but I cannot get the answer no matter what I do.

I have attached a picture of the problem as I have worked it out.

For part (a) I have 75.8028368 km
for part (b) I have 32.4163299 degrees north of east

I am allowed a -/+7% tolerance.
 

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The answers are

(a) 74.054828934557 km


(b) 42.458201635351 ° north of east

I was fairly close on the magnitude, but I do not know why I am not getting the angle.
 

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