Addition of Angular Momenta, problem with notation

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SUMMARY

The discussion centers on expressing the superposition state of an electron in a hydrogen atom, given by |\psi> = \frac{1}{\sqrt{2}}(|n=2,l=1,m=0,s_z= +1/2> + |n=2,l=0,m=0,s_z= +1/2>), in the basis |n, l, J, J_z>. The total angular momentum J is defined as J = L + S, where L is the orbital angular momentum and S is the spin angular momentum. The transformation between the two bases utilizes Clebsch-Gordan coefficients, specifically referencing the table on page 188 of Griffiths. The challenge lies in correctly identifying the values of J and J_z for the state with no orbital angular momentum (l=0).

PREREQUISITES
  • Understanding of quantum mechanics concepts such as angular momentum and superposition.
  • Familiarity with Clebsch-Gordan coefficients and their application in quantum state transformations.
  • Knowledge of quantum state notation, specifically |n, l, m, s_z> and |n, l, J, J_z> forms.
  • Basic proficiency in using Griffiths' "Introduction to Quantum Mechanics" as a reference for angular momentum.
NEXT STEPS
  • Study the application of Clebsch-Gordan coefficients in quantum mechanics.
  • Learn how to convert between different angular momentum bases in quantum states.
  • Review the properties of eigenstates related to total angular momentum J and its components.
  • Examine examples of superposition states in quantum mechanics to solidify understanding.
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Students and educators in quantum mechanics, particularly those focusing on angular momentum, as well as researchers needing clarity on state transformations in quantum systems.

joelcponte
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Homework Statement


The electron in a hydrogen atom is described by the following superposition of two states:

|\psi> = \frac{1}{\sqrt{2}}(|n=2,l=1,m=0,s_z= +1/2> + |n=2,l=0,m=0,s_z= +1/2>)

(b) Let J = L + S be the total angular momentum. Express state \psi in basis |n, l, J, J_z>
Hint: use the Clebsch -Gordan coffecients from the table on pg. 188 of Griffiths.

Homework Equations



|s_1 m_1>|s_2 m_2> = \sum C^{s_1s_2s}_{m_1m_2m}|s m>


The Attempt at a Solution



For the first state:

|n=2,l=1,m=0,s_z= +1/2> ====> l=1, s = 1/2
|1,0>|1/2,1/2> = \sqrt{\frac{2}{3}}|3/2,1/2> - \sqrt{\frac{1}{3}}|1/2,1/2>

For the second state:

|n=2,l=0,m=0,s_z= +1/2> ====> there's no orbital angular momentum

My question is: I don't know if what I've done is correct and, if it is, I don't know how to transform to the notation he asks. For me, the "l" in the new notation doesn't make sense or have to be 0.
 
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joelcponte said:

Homework Statement


The electron in a hydrogen atom is described by the following superposition of two states:

|\psi> = \frac{1}{\sqrt{2}}(|n=2,l=1,m=0,s_z= +1/2> + |n=2,l=0,m=0,s_z= +1/2>)

(b) Let J = L + S be the total angular momentum. Express state \psi in basis |n, l, J, J_z>
Hint: use the Clebsch -Gordan coffecients from the table on pg. 188 of Griffiths.

Homework Equations



|s_1 m_1>|s_2 m_2> = \sum C^{s_1s_2s}_{m_1m_2m}|s m>


The Attempt at a Solution



For the first state:

|n=2,l=1,m=0,s_z= +1/2> ====> l=1, s = 1/2
|1,0>|1/2,1/2> = \sqrt{\frac{2}{3}}|3/2,1/2> - \sqrt{\frac{1}{3}}|1/2,1/2>
That's right.

For the second state:

|n=2,l=0,m=0,s_z= +1/2> ====> there's no orbital angular momentum
So what are j and jz equal to in this case?

My question is: I don't know if what I've done is correct and, if it is, I don't know how to transform to the notation he asks. For me, the "l" in the new notation doesn't make sense or have to be 0.
You have one basis with states of the form ##\lvert \ l\ m_l \rangle \lvert\ s\ m_s \rangle##. These states are eigenstates of L2, Lz, S2, and Sz. The other basis has states of the form ##\lvert \ l\ s\ j\ j_z\rangle##, which are eigenstates of L2, S2, J2, and Jz. These two bases are related through the Clebsch-Gordan coefficients.

When you wrote
$$\lvert 1,0\rangle \lvert 1/2,1/2\rangle = \sqrt{\frac{2}{3}} \lvert 3/2,1/2\rangle - \sqrt{\frac{1}{3}} \lvert1/2,1/2\rangle,$$ what it really means is
$$\lvert 1,0\rangle \lvert 1/2,1/2\rangle = \sqrt{\frac{2}{3}} \lvert l=1, s=1/2, j=3/2, j_z=1/2\rangle - \sqrt{\frac{1}{3}} \lvert l=1, s=1/2, j=1/2, j_z=1/2\rangle,$$
 

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