Addition of angular momentum - Finding the second tower states

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Homework Help Overview

The discussion revolves around calculating the states for a quantum system characterized by angular momentum, specifically with total angular momentum quantum numbers ##l=1## and ##s=1/2##. The original poster is focused on determining the Klebsch-Gordon coefficients for the second tower of states, which corresponds to the total angular momentum ##j=1/2##.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster has successfully calculated the states for ##j=3/2## but is uncertain about how to find the states for ##j=1/2##. They express confusion about how to represent the state ##|j,j_z>=|1/2, 1/2>## using the individual angular momentum states ##l_z## and ##s_z##. Other participants suggest considering the orthogonality of the states and the implications of the total angular momentum operator.

Discussion Status

The discussion is ongoing, with participants exploring the relationships between the states and the requirement for orthogonality. Some guidance has been provided regarding the known states and their properties, but there is no explicit consensus on the next steps or resolution of the original poster's confusion.

Contextual Notes

Participants are navigating the complexities of angular momentum coupling and the implications of the quantum mechanical operators involved. There is an acknowledgment of the need for orthogonality in the states, which may influence the approach to finding the required representations.

DataGG
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Homework Statement



I'm supposed to calculate all the states for a system with ##l=1## and ##s=1/2##. Let's say ##\vec{J} = \vec{L} + \vec{S}##. I want to find the Klebsch-Gordon coefficients.

I know that said system has 2 towers, one with ##j=3/2## and the other with ##j=1/2##. I've calculated all the states for ##j=3/2## but now I'm having some problems with ##j=1/2##.

So, for the second tower, we've two states: ##|j,j_z>=|1/2, 1/2>## and ##|j,j_z>=|1/2, -1/2>##

How am I supposed to find ##|j,j_z>=|1/2, 1/2>##? If I do that, finding ##|j,j_z>=|1/2, -1/2>## should be easily done by applying the ##J _## operator.

Homework Equations



$$J _ |j, j_z>=\hbar \sqrt{j(j+1)-j_z(j_z-1)}|j,j_z-1>$$
$$S _ |s, s_z>=\hbar \sqrt{s(s+1)-s_z(s_z-1)}|s,s_z-1>$$
$$L _ |j, j_z>=\hbar \sqrt{l(l+1)-l_z(l_z-1)}|l,l_z-1>$$

The Attempt at a Solution



Well, I've done well for the tower with ##j=3/2##. Now with this second tower, I don't know where to begin from. I think this is because for ##j = j_z = 3/2##, we know that ##j_z = l_z + s_z## which means ##l_z =1 ## and ##s_z = 1/2##. There's no other way.

For the case with ##j=1/2##, we've two options. ## l_z=0, s_z=1/2##, which is to say ##|l_z,s_z>=|0, 1/2> ## and ##l_z=1, s_z=-1/2##, which is to say ##|l_z,s_z>=|1, -1/2>##. Should I sum those states somehow?
 
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You already know that one of the jz = 1/2 states is part of the j=3/2 representation. Since there are only two of those, which is the remaining one?
 
Orodruin said:
You already know that one of the jz = 1/2 states is part of the j=3/2 representation. Since there are only two of those, which is the remaining one?

I'm not sure I understand what you're saying.. I know that, for ##j_z = 1/2## there's two states. One being for ##j=3/2## and the other for ##j=1/2##. That is:

##|j, j_z> = |3/2, 1/2>## and ##|j, j_z> = |1/2, 1/2>##. Now I need to write this last state using ##l_z## and ##s_z##, in order to find the Klebsch-Gordon coefficients.
 
Yes, I am fully aware of that. What I am saying is that you know what the state with ##j_z = 1/2## and ##j = 3/2## is, since you have already computed the states with ##j = 3/2##. The state you are searching for must be orthogonal to this.
 
Orodruin said:
Yes, I am fully aware of that. What I am saying is that you know what the state with ##j_z = 1/2## and ##j = 3/2## is, since you have already computed the states with ##j = 3/2##. The state you are searching for must be orthogonal to this.

Oh! I forgot that. I don't know why they need to be orthogonal though, but I guess that's a discussion for another thread. I'll see if I can solve it having that in mind!

Thank you Orodruin!
 
DataGG said:
I don't know why they need to be orthogonal though

What can you say about the operator ##\hat J = \hat L + \hat S##?
 

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