Adiabat Process - with pV cycle

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hevans1303
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Homework Statement



A heat engine uses 2 mole of a diatomic gas that follows the pV cycle shown, how much work is done, over the cycle if P=100kPa, T1=207K


pV diagram of a three-state cycle: state 1 to 2 is a vertical rise at constant volume, 2 to 3 is an adiabat falling to the right, and 3 back to 1 is an isotherm. Axes are p (kPa) and V (cm3), with marks at P, 2P, V and 2V.

* P is suppose to be 0.5P this was a typo on the graph


This is what I've figured out so far: (if i am incorrect on anything please let me know)

W1→2 = 0

W2→3=nRΔT
So it would look like:
(2)(5/2)(8.31)(?-207)
The problem is i can't figure out how to find the other tempurature

W3→1=nRTln(v2/v1)
So it would look like this
(2)(8.31)(207)ln(?/?)
I don't understand how to get the volumes in this problem all the other problems i have had have given me a volume.