Adiabatic Process: Final Temp & Heat Absorbed Calculation

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SUMMARY

The discussion centers on an adiabatic process involving twenty moles of a monatomic ideal gas with an initial pressure of 400 kPa and an initial temperature of 450 K, ultimately reaching a final temperature of 320 K. The key conclusion is that the heat absorbed by the gas during this process is zero, as defined by the equation Q=0, which is characteristic of adiabatic processes. Participants agree that despite changes in temperature, no heat is exchanged with the surroundings, confirming that the correct answer to the posed question is 0 kJ.

PREREQUISITES
  • Understanding of adiabatic processes in thermodynamics
  • Familiarity with the ideal gas law
  • Knowledge of monatomic ideal gas properties
  • Basic grasp of thermodynamic equations, specifically Q=0
NEXT STEPS
  • Study the principles of thermodynamics related to adiabatic processes
  • Explore the ideal gas law and its applications in real-world scenarios
  • Learn about the behavior of monatomic gases under varying conditions
  • Investigate other thermodynamic processes, such as isothermal and isobaric processes
USEFUL FOR

This discussion is beneficial for students studying thermodynamics, physics enthusiasts, and professionals in engineering fields who require a solid understanding of gas behavior during adiabatic processes.

jimbo71
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Homework Statement


twenty moles of a monatomic ideal gas (lambda=5/3) undergo an adiabatic process the initial pressure is 400kpa and the initial temperature is 450K. The final temperature of the gas is 320K.
The heat absorbed by the gas in kJ is closest to?
a.0
b.+54
c.+32
d.-54
e.-32

Homework Equations


Q=0



The Attempt at a Solution


I think this is suppose to be a trick question. I thought an adiabatic process ment zero heat was gained or lost. Therefore shouldn't the answer be zero regardless of the temperature, moles, or pressure values given?
 
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An adiabatic process won't add or take heat away from a gas. It doesn't mean that the gas itself cannot change temperature as a result of say an increase in pressure. Since the question asks how much was absorbed and they have indicated it is adiabatic, then ... 0 looks to be the answer.
 

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