Isothermal, isobaric and adiabatic

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Sabra_a
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Homework Statement
Ideal gas expands from volume V1 to volume V2 in three different
regimes: isothermal, isobaric and adiabatic, Fig.Q1.

(i) Identify the regimes (isothermal, isobaric, adiabatic) with the
curves (1-2, 1-3, 1-4).

(ii) In which of three expansion regimes the gas will perform the
larger work?

(iii) In which of three expansion regimes the larger heat will be
transferred to the gas?
Relevant Equations
ideal gas
first law of thermodynamics
(i) In this case the gas is expanding therefore its volume will increase and the pressure will drop. As volume gets bigger particles have more space to move around.

Isobaric is curve (1-2). It’s a horizontal line because here the pressure is constant.

Isothermal is curve (1-3) temp is constant here, energy added to the system through work, the is no change in internal energy. Fromperfect gas equation
Equation PV = mRT, where P is pressure, V is volume, m is mass, R is the gas constant and T is temperature.
, m, R and temperature are constant therefore PV = constant,
Equation for a constant-pressure relation: P = constants / V, written as a fraction with P on the left and a numerator of constants over V on the right.
and that’s similar to rectangular hyperbola
Adiabatic curve is (1-4) there is no heat transfer into or out of the system.

The internal energy of gas will decrease. As the gas expands it will cool down and lose its kinetic energy therefore temperature will decrease. The internal energy equal the work done on the gas as there is no heat supply to the gas. The gas is doing work on the environment to expand. Here the gas will end up on a lower pressure. That’s why the curve is steeper.

(ii) The area under the curve gives the work done in a system. If expansion is occurring, isothermal will perform the larger work.
In isobaric from the first law of thermodynamics
Equation: change in internal energy ΔU = Q + (−PΔV), where Q is heat added and PΔV is work done by the gas.

In isothermal process the internal energy U = 0
From the first law of thermodynamics
Thermodynamics equation: change in internal energy ΔU = Q + W, written as a single line with the terms ΔU, Q and W.
as
1573041525750.png
, heat flow intothe gas (Q) and work done on the gas (W) add up to zero.
1573041526040.png
. The work here is done more on the surrounding. Because the temperature is constant the internal energy didn’t change energy had to be added to the system to make up the work done. The heat get transferred from the surroundings to do the worktherefore isothermal process does more work than the adiabatic. The heat transferred to the gas keeps its temperature constant higher pressure and more work done
whereas for adiabatic heat flow (Q) = 0, From the first law of thermodynamics
Thermodynamics equation: change in internal energy ΔU = Q + W, written in a small rendered box.
as
1573041526230.png
, internal energy
1573041526412.png
there it means that the system's used its internal energy to perform its work

(iii) Adiabatic curve (1-4) there is no heat transfer into or out of the system, therefore its excluded.Isobaric curve (1-2) heat is transferred to the system to keep the pressure constant where Isothermal curve (1-3) temperature is constant and the internal energy is equal to zerobecause the temperature is constant the internal energy didn’t change energy had to be added to the system to make up the work done. Therefore, Isobaric has the largest heat transfer.
 
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I attached a PDF file!
I can't paste the graph here
 
Last edited:
Sabra_a said:
I attached a PDF file!
I can't paste the graph here
You shouldn't force homework helpers to open files.

Your answers appear correct.
 
thank you but I wasn't forcing, I thought the answer will be more clear while looking into a graph. I don't think this should be considered as a no effort
 
Sabra_a said:
I thought the answer will be more clear while looking into a graph.
Indeed it would be, but the graph should appear within your post and not in an attachment (see below).
Figure Q1: p-V diagram with points 1, 2, 3 and 4. A horizontal line runs from point 1 to point 2 at the same pressure, with V1 and V2 marked on the volume axis. Curves from point 1 descend to points 3 and 4 at V2.

If I can post your figure, you can post your figure. If you cannot figure out how to do it, just ask.
 
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