B Advice to obtain the domain of compound functions

  • B
  • Thread starter Thread starter mcastillo356
  • Start date Start date
  • Tags Tags
    Domain Functions
AI Thread Summary
The discussion revolves around understanding the domain of the inverse secant function, sec^{-1} x, and how it relates to the cosine function. The domain is defined as the union of intervals (-∞, -1] and [1, ∞), along with specific ranges for the inverse function. The user seeks guidance on determining the domain and range of cos^{-1}(1/x) using only the known domains of arccos(x) and the reciprocal function. There is also a query about a potential typo regarding the reflection of the secant function in relation to its inverse. The thread concludes with a technical note about formatting issues encountered while posting formulas.
mcastillo356
Gold Member
Messages
639
Reaction score
348
TL;DR Summary
I'm familiar to this ground, but the function composition I introduce is difficult for me
Hi PF

I have a quote from Spanish 6th edition of "Calculus", by Robert A. Adams, and some queries. I translate it this way:"The inverse of secondary trigonometric functions can easily be calculated with the reciprocal function. For example
DEFINITION 13 The inverse function of secant ##sec^{-1} x## (or ##\mbox{arcsec}x##)
$$sec^{-1}=cos^{-1}\left({\dfrac{1}{x}}\right)\quad for\;|x|\geq 1$$
The domain of ##\sec^{-1}## is the union of intervals ##(-\infty,-1]\cup{[1,\infty)}## and ##[0,\dfrac{\pi}{2})\cup{(\dfrac{\pi}{2},\pi)}##. The graph of ##y=sec^{-1}x## is shown in Figure 3.25(b)(*). Is the reflection respect to the line ##y=x## of the part of ##\sec x## for ##x## between 0 and ##\pi##. Additionally
$$\sec(\sec^{-1}x)=\sec\left({\cos^{-1}\left({\dfrac{1}{x}}\right)}\right)
=\dfrac{1}{\cos\left({\cos^{-1}\left({\dfrac{1}{x}}\right)}\right)}=\dfrac{1}{\dfrac{1}{x}}=x\qquad{\mbox{for}\;|x|\geq 1}$$Up to now I've got to deal only with very easy compound functions. This quote represents a qualitative step forward. The domains and ranges are shown, but I would like to know: what if I had to do it by myself, if I was given only the identities, and had to manage to describe the domain and range of, suppose, the one at DEFINITION 13?

$$cos^{-1}\left({\dfrac{1}{x}}\right)$$

With no other help but the knowledge of the domain of ##y=\mbox{arcos}(x)##, ##(-1\leq x\leq 1)##, and ##\mathbb{R}\setminus{\{0\}}## for ##\dfrac{1}{x}##

As well, isn't there a mistake, a typo, at the sentence "Is the reflection respect to the line ##y=x## of the part of ##\sec x## for ##x## between 0 and ##\pi##"? Shouldn't be "of the part of ##sec^{-1} x##"?.

(*)Attached image

Attempt: Pure speculation; don't know why, but I've come across this statement: domain shouldn't be the intersection of the domain of ##y=\cos x## and the domain of the inverse function of ##y=\dfrac{1}{x}##?
 

Attachments

  • geogebra-export (2).png
    geogebra-export (2).png
    23.7 KB · Views: 132
Last edited by a moderator:
Mathematics news on Phys.org
I've typed the formulas with #### and $$$$. Why didn't I post successfully?. :oldcry:
 
mcastillo356 said:
I've typed the formulas with #### and $$$$. Why didn't I post successfully?. :oldcry:
You have simple forgotten a single "#" somewhere early. That was all. I corrected it.
 
  • Love
Likes mcastillo356
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...

Similar threads

Replies
2
Views
1K
Replies
7
Views
1K
Replies
2
Views
996
Replies
5
Views
1K
Replies
5
Views
1K
Replies
11
Views
1K
Back
Top