Affine Varieties - the x-axis in R^2

  • Level: Graduate 
  • Thread starter Math Amateur
  • Start date
1 reply · 2K views · last reply
Math Amateur
Gold Member
MHB
Messages
3,920
Reaction score
48
In Dummit and Foote, Chapter 15, Section 15.2 Radicals and Affine Varieties, Example 2, page 681 begins as follows:

-----------------------------------------------------------------------------------------
"The x-axis in [itex]\mathbb{R}^2[/itex] is irreducible since it has coordinate ring

[itex]\mathbb{R}[x,y]/(y) \cong \mathbb{R}[x][/itex]

which is an integral domain."

------------------------------------------------------------------------------------------

Can someone please help me to show formally and rigorously how the isomorphism

[itex]\mathbb{R}[x,y]/(y) \cong \mathbb{R}[x][/itex] is established.


I suspect it comes from applying the First (or Fundamental) Isomorphism Theorem for rings ... but I am unsure of the mappings involved and how they are established

Would appreciate some help>

Peter
 
Consider ##\Phi: R[X,Y]\rightarrow R[X]: \sum \alpha_{ij}X^i Y^j \rightarrow \sum \alpha_{i0}X^i##. So we evaluate the polynomial in ##0##. These evaluation maps usually work in these contexts.
 
  • Like
Likes   Reactions: 1 person