Affine Varieties - the x-axis in R^2

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In Dummit and Foote, Chapter 15, Section 15.2 Radicals and Affine Varieties, Example 2, page 681 begins as follows:

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"The x-axis in [itex]\mathbb{R}^2[/itex] is irreducible since it has coordinate ring

[itex]\mathbb{R}[x,y]/(y) \cong \mathbb{R}[x][/itex]

which is an integral domain."

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Can someone please help me to show formally and rigorously how the isomorphism

[itex]\mathbb{R}[x,y]/(y) \cong \mathbb{R}[x][/itex] is established.


I suspect it comes from applying the First (or Fundamental) Isomorphism Theorem for rings ... but I am unsure of the mappings involved and how they are established

Would appreciate some help>

Peter
 
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Consider ##\Phi: R[X,Y]\rightarrow R[X]: \sum \alpha_{ij}X^i Y^j \rightarrow \sum \alpha_{i0}X^i##. So we evaluate the polynomial in ##0##. These evaluation maps usually work in these contexts.
 
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