AICc value derivation (Akaike information criteria for finite samples)

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SUMMARY

The discussion focuses on the derivation of the AICc (Akaike Information Criterion corrected for finite samples) formula, specifically the additional penalty term $$\frac {2k^2+2k} {n-k-1}$$. This term adjusts the AIC for the number of parameters (k) in relation to the sample size (n). As the sample size approaches infinity, AICc converges to AIC, indicating that the penalty becomes negligible. The user seeks proof for the derivation of this extra term in the context of finite samples.

PREREQUISITES
  • Understanding of AIC (Akaike Information Criterion)
  • Familiarity with ARIMA (AutoRegressive Integrated Moving Average) models
  • Basic knowledge of statistical concepts such as sample size and parameters
  • Mathematical proficiency to comprehend derivations involving limits and ratios
NEXT STEPS
  • Research the derivation of AIC and its application in model selection
  • Study the implications of finite sample corrections in statistical modeling
  • Explore the differences between AIC and AICc in practical scenarios
  • Learn about other model selection criteria such as BIC (Bayesian Information Criterion)
USEFUL FOR

Statisticians, data scientists, and researchers involved in model selection and evaluation, particularly those working with time series analysis using ARIMA models.

mertcan
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Hi everyone, initially let me introduce a concept widely used in ARIMA in the following. $$AICc = AIC + \frac {2k^2+2k} {n-k-1}$$ where n denotes the sample size and k denotes the number of parameters. Thus, AICc is essentially AIC with an extra penalty term for the number of parameters. Note that as n → ∞, the extra penalty term converges to 0, and thus AICc converges to AIC. I have derived AIC value but could provide me with the proof of the extra term $$\frac {2k^2+2k} {n-k-1}$$ particularly used in finite samples?
 
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