Air flow pipe size reduction|Incompressible&Lossless COMPLETED ANSWER

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SUMMARY

The discussion focuses on calculating pressure changes and forces in a horizontal air duct that reduces in size from 0.75 m² to 0.20 m², with a mass flow rate of 6 kg/s and a density of 3.2 kg/m³. Using Bernoulli's equation, the pressure difference calculated is 130.625 Pascals. The incompressible assumption for air is deemed unjustified due to the nature of gases, which can compress. The force transmitted by the jet striking a vertical wall is calculated to be 28.125 N, derived from dynamic pressure and area considerations.

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  • Understanding of Bernoulli's equation
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  • Familiarity with mass flow rate calculations
  • Basic concepts of pressure and force in fluid systems
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Mechanical engineers, fluid dynamics specialists, and students studying fluid mechanics will benefit from this discussion, particularly those focusing on air flow systems and pressure calculations.

DylanW
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Homework Statement



Q4. A horizontal air duct reduces from 0.75 m2
to 0.20 m2
.
a) Assuming no losses and an incompressible fluid, what pressure change will occur when 6 kg/s
of air flows through the duct? Use a density of 3.2 kg/m3
for these conditions.
b) Is the incompressible assumption justified?
c) If the jet exits the smaller pipe and strikes a vertical wall, what force will it transmit?


Homework Equations



MassFlowRate = rho.V.A
Bernoullis



The Attempt at a Solution



rho(A).Velocity(A).Area(A)=mass flowate therefore Velocity(A) = 2.5
Mass Flow Rate is Constant
rho(A).Velocity(A).Area(A)=rho(B).Velocity(B).Area(B) therefore Velocity(B) = 9.375
Bernoullis - can't be bothered typing original equation will just type final rearrangement
Pressure(A) - Pressure(B) = [(Velocity(B)^2 - Velocity(A)^2)Rho]/2 which equals 130.625 Pascals pressure difference. Seems a bit low?

For part b, is the incompressible assumption justified? I don't think that it is, because it's density it is a gas and would definitely compress which may explain the results from part A?

For Part C) I'm not so sure of this, I think it would be the Absolute pressure over the area of the Jet so (x Pascals / 0.2 m^2) but I am not sure how to find the absolute pressure, only the difference. Thanks :D
 
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For Part C, I've used the equation P(Dynamic) = [rho.V^2]/2 giving a dynamic pressure of 140.625 Pa and verifying my answer from part 1. Then Using P=F/A -> F = PA I've calculated a force of 28.125N. I am worried that I am ignoring static pressure but I can't see any other way with the information provided.
 

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