Algebra 4th power weirdness problem

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The equation 4x - x^4/8 = 6 can be transformed into the polynomial equation x^4 - 32x + 48 = 0. This polynomial can be factored as (x - 2)(x^3 + 2x^2 + 4x - 24) = 0, revealing that x = 2 is one of its roots. The rational roots theorem is a critical tool for identifying potential rational solutions to polynomial equations, which likely guided the solution process in this discussion.

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How did he get x = 2 with this equation? 4x - x^4/8 = 6

Here's my solution:
32x - x^4 - 48
x( x^3 - 32 ) + 48 <---- Now I'm lost. Did he use this one? (a-b)(a^2+ab+b^2) . I tried it but can't think on what to extract.

http://www.wolframalpha.com/input/?i=4x-x^4%2F8%3D6
 
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First off, this is an equation: 4x - x^4/8 = 6
This is NOT an equation: 32x - x^4 - 48 -- An equation has an = sign.

The equation is 32x - x^4 - 48 = 0, or equivalently x^4 - 32x + 48 = 0.
This equation can be factored into (x - 2)(x^3 + 2x^2 + 4x -24) = 0.
 
"He" would have probably used the rational roots theorem first, if not given any more information.
 

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