Algebra- find solution using two variables

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Homework Help Overview

The problem involves a chemist needing to create a 72 ml solution of 12% alcohol using available 8% and 20% alcohol solutions. Participants are discussing the formulation of equations to represent the amounts of each solution required.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to establish equations based on the concentrations of the alcohol solutions and the total volume required. There is a focus on understanding how to represent the amounts of alcohol in each solution and how these relate to the desired final concentration.

Discussion Status

The discussion is ongoing, with participants providing insights into the relationships between the variables and questioning the assumptions made in the initial setup. Some have suggested multiplying the percentage by the total volume to find the amount of alcohol needed, while others emphasize the need for a second equation to account for the total volume of the mixture.

Contextual Notes

There is a mention of needing to clarify what x + y represents in the context of the problem, indicating a potential gap in understanding the relationship between the variables and the total solution volume.

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Homework Statement


A chemist ran out of a 72 ml solution of 12% alcohol. All that is left in the lab is 8% alcohol and 20% alcohol. How many ml of 8% and 20% would be needed to make a 72 ml solution of 12%?


Homework Equations





The Attempt at a Solution


8x + 20y = 12
 
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What would x+ y represent in this situation?

Of course, if you have x ml of 8% solution then .08x (not "8x") would be the amount of alcohol in it and if you have y ml of 20% solution then .20y would be the amount of alcohol in that. So .08x+ .20y would be the amount of alcohol in the combined soltion. But that is NOT 12 or .12. .12 is the percentage of alcohol in the 72 ml solution. What do you need to multiply the .12 by to get the amount of alcohol? You can then multiply the entire equation by 100 to get rid of the decmals.
 
Would I multiply .12 by 72 ? Which would then be 8.64

This is what I have so far.

.12 X 72=8.64

.08x + .2y=8.64

(100) .08x + .2y=8.64 (100)

8x + 20y= 864
 
Last edited:
8x+20y=864 that is good for amount of alcohol
but you are missing one more equation, what's the total amount of liquid that should be made ?
 
puma072806 said:

Homework Statement


A chemist ran out of a 72 ml solution of 12% alcohol. All that is left in the lab is 8% alcohol and 20% alcohol. How many ml of 8% and 20% would be needed to make a 72 ml solution of 12%?


Homework Equations





The Attempt at a Solution


8x + 20y = 12

One way to think about such problems is to realize that the figures 12%, 8% and 20% are, essentially, measures of the number of alcohol molecules in a ml of solution. (The actual numbers could be found by going to physical/chemical tables and computing some conversion factors.) When you take a bottle of V1 ml of 8% solution (containing N1 alcohol molecules) and V2 ml of 20% solution (containing N2 alcohol molecules), how much solution do you have altogether? How many alcohol molecules are in the new solution? How does that translate into percentage terms?
 
HallsofIvy said:
What would x+ y represent in this situation?

Of course, if you have x ml of 8% solution then .08x (not "8x") would be the amount of alcohol in it and if you have y ml of 20% solution then .20y would be the amount of alcohol in that. So .08x+ .20y would be the amount of alcohol in the combined soltion. But that is NOT 12 or .12. .12 is the percentage of alcohol in the 72 ml solution. What do you need to multiply the .12 by to get the amount of alcohol? You can then multiply the entire equation by 100 to get rid of the decmals.

puma072806 said:
Would I multiply .12 by 72 ? Which would then be 8.64

This is what I have so far.

.12 X 72=8.64

.08x + .2y=8.64

(100) .08x + .2y=8.64 (100)

8x + 20y= 864

The big hint is, again, what does x+y represent? What exactly does this example chemist want? Your original equation was good, but you need one more equation.

What HallsofIvy is trying to explain is that you can use decimal fractions instead of percentage, so your first equation can be
0.08x+0.20y=0.12
 
Last edited:

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