zak100 said:Homework Statement
If the average (arithmetic mean) of 3a and 4b is less than 50, and a is twice b, what is the largest possible integer value of a?
Homework Equations
Avg of two variables is:
(a+b)/2
The Attempt at a Solution
(3a + 4b)/2 < 50
3a + 4b <100
Now try out values such a = 2b
I) a= 10 & b=20
3(10) + 4(20) <100
30 + 80 <100
110<100 false
2) a=9 & b = 18
3(9) + 4(18)
27 + 72
99
but this answer is not correct. Some body please guide me.
Zulfi.
Yes, unless b is also supposed to be an integer. I agree it does not say so.zak100 said:i.e a =19
The average of two terms is the sum of the two terms divided by 2. It is also known as the arithmetic mean.
To find the average of two terms, add the two terms together and divide the sum by 2. This will give you the average of the two terms.
The largest possible value of two terms depends on the numbers being used. If the two terms are positive, the largest possible value would be when both terms are equal. If the two terms are negative, the largest possible value would be when one term is close to 0 and the other is a large negative number.
Yes, the average of two terms can be a negative number if one term is positive and the other is negative. The negative average indicates that the terms are on opposite sides of 0.
The average of two terms is useful in mathematics and science as it allows us to find the middle point between two values. This can be helpful in calculating trends, making predictions, and determining the central tendency of a data set.