- #1
MathJakob
- 161
- 5
##\frac{6-2x}{x^2-9}\times\frac{15+5x}{4x}##
##\frac{2(3-x)}{(x-3)(x+3)}\times\frac{5(3+x)}{4x}##
##\frac{3-x}{x-3}\times\frac{5}{2x}##
Now do I make the assumption that ##x\neq3## ?
If I make the assumption that ##x\neq3## then ##-1\times\frac{5}{2x} = -\frac{5}{2x}##
##\frac{2(3-x)}{(x-3)(x+3)}\times\frac{5(3+x)}{4x}##
##\frac{3-x}{x-3}\times\frac{5}{2x}##
Now do I make the assumption that ##x\neq3## ?
If I make the assumption that ##x\neq3## then ##-1\times\frac{5}{2x} = -\frac{5}{2x}##