- #1
CuriousBanker
- 190
- 24
Hello
So I'll be going back to school for math next semester, so I might not know the answer to this because I haven't taken combinatorics. I only really know algebra one and two, calc one and some trig.
Anyway, currently studying for my cfa, and it's easy enough to plug the formulas in, but they don't show you how they were derived. So for the two following formulas:
1) P(ab) = p(a) x p(b) (like the chance of getti two heads on two consecutive coin flips
2) p (a|b) = p(ab)/p(b) (conditional probability)
They both make intuitive sense and I can prove them wih a tree diagram but I am just curious if there's an algebraic proof
Thanks I advance, probably a simple answer
So I'll be going back to school for math next semester, so I might not know the answer to this because I haven't taken combinatorics. I only really know algebra one and two, calc one and some trig.
Anyway, currently studying for my cfa, and it's easy enough to plug the formulas in, but they don't show you how they were derived. So for the two following formulas:
1) P(ab) = p(a) x p(b) (like the chance of getti two heads on two consecutive coin flips
2) p (a|b) = p(ab)/p(b) (conditional probability)
They both make intuitive sense and I can prove them wih a tree diagram but I am just curious if there's an algebraic proof
Thanks I advance, probably a simple answer