- #1
gtguhoij
- 33
- 2
- Homework Statement
- Alice flies past Bob at speed v. Right when she passes, they both set their watches to zero. When Alice’s watch shows a time T, she waves to Bob. Bob then waves to Alice simultaneously (as measured by him) with Alice’s wave (so this is before he actually sees her wave). Alice then waves to Bob simultaneously (as measured by her) with Bob’s wave. Bob then waves to Alice simultaneously (as measured by him) with Alice’s second wave. And so on. What are the readings on Alice’s watch for all the times she waves? And likewise for Bob?
- Relevant Equations
- ## t' = gamma (t - \frac {xv} {c^2}) ##
assuming I am understand the question correctly Bob and Alice have the same location in both frames.
Event 0 everything is 0.event 1
I assume both Alice and Bob are at the same location for every location. So I am just doing the calculations once for
Alice's frame for Alice and Bob's frame for Bob. I am not sure if the question asked it but I also did prime frame for Alice and Bob.##
gamma = 2
v = .866c
t = 1 sec
##
I go
## d = vt = (1 s)(.866c) = .866LS ## (for Lorentz transform)
Then t = 2 I could do the calculation or multiply everything by 2. For t = 3 multiply by 3 etc
Now to find t' for event 1
## t' = gamma (t - \frac {xv} {c^2}) ##
## t' = 2(1 sec - (.866LS)(.866c) ) ##
## t' = .5 sec ##.
Now to get event 2 variables multiply time by 2 to get event 3 multiply 3.
Here is my basic formula
## t_event_number = t ~ 1 ~or ~t' ~ 1 (event ~number) ##
## t~event~number = t ~, 1 ##
## t'~ event~ number = t ~1' ##Let me show an example
## t1' = .5 ## and ## t1 = 1##
While, ## event ~number = 0 - infinity##
Is this correct? Or my assumption that Alice and Bob can have the same location incorrect?
Event 0 everything is 0.event 1
I assume both Alice and Bob are at the same location for every location. So I am just doing the calculations once for
Alice's frame for Alice and Bob's frame for Bob. I am not sure if the question asked it but I also did prime frame for Alice and Bob.##
gamma = 2
v = .866c
t = 1 sec
##
I go
## d = vt = (1 s)(.866c) = .866LS ## (for Lorentz transform)
Then t = 2 I could do the calculation or multiply everything by 2. For t = 3 multiply by 3 etc
Now to find t' for event 1
## t' = gamma (t - \frac {xv} {c^2}) ##
## t' = 2(1 sec - (.866LS)(.866c) ) ##
## t' = .5 sec ##.
Now to get event 2 variables multiply time by 2 to get event 3 multiply 3.
Here is my basic formula
## t_event_number = t ~ 1 ~or ~t' ~ 1 (event ~number) ##
## t~event~number = t ~, 1 ##
## t'~ event~ number = t ~1' ##Let me show an example
## t1' = .5 ## and ## t1 = 1##
While, ## event ~number = 0 - infinity##
Is this correct? Or my assumption that Alice and Bob can have the same location incorrect?
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