Alpha particle approaching gold nucleus

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 3K views
gilson.fisica
Messages
2
Reaction score
0
An alpha particle is thrown toward a gold nucleus. An alpha particle has two neutrons and two protons and a load module 2e, where "e" is the electron charge, while the gold nucleus has 79 protons and a load module 79e. What is the minimum kinetic energy that the alpha particle must have in order to approach to a distance of 50fm the center of the gold nucleus? Assume that the gold core, which rest mass is fifty times greater than the rest mass of the alpha particle.

It's okay to use the equation: k = 2Ze^2/1.pi.Eo.r ?? E = epsilon
Where this is not suitability, know not solve. Help please

Thank...
 
Physics news on Phys.org
Apart from the formatting error, the approach looks good, but I think the prefactor is wrong (should be 4 pi in the denominator).

Edit: I changed the topic to give a better description of the problem.
 
Last edited:
Really there was a typing error; k = 2Ze^2/4.pi.Eo.r... Thank you! :)