Alpha Particle-Gold Nucleus Collision: Solving for Initial and Final Momentum

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SUMMARY

The discussion focuses on calculating the initial and final momentum of an alpha particle colliding with a gold nucleus. The alpha particle has a kinetic energy of 9.5 MeV, and the gold nucleus is initially at rest. The initial momentum of the alpha particle is determined using classical mechanics, specifically the kinetic energy formula \(K = \frac{1}{2} mv^2\). The final momentum calculations require applying the conservation of momentum and energy principles, with the suggestion to use a Rutherford scattering approach rather than relativistic methods.

PREREQUISITES
  • Understanding of classical mechanics principles, particularly momentum and kinetic energy.
  • Familiarity with the concept of conservation of momentum and energy.
  • Knowledge of alpha particles and nuclear structure, specifically helium and gold nuclei.
  • Basic proficiency in algebra for solving equations related to kinetic energy and momentum.
NEXT STEPS
  • Study the derivation of momentum from kinetic energy using \(K = \frac{1}{2} mv^2\).
  • Research Rutherford scattering to understand collision dynamics at the nuclear level.
  • Explore conservation laws in physics, focusing on momentum and energy conservation in collisions.
  • Learn about the properties of alpha particles and their interactions with heavy nuclei like gold.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in nuclear physics and collision dynamics, particularly in understanding momentum calculations in particle interactions.

lebprince
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Homework Statement



An alpha particle (a helium nucleus, containing 2 protons and 2 neutrons) starts out with kinetic energy of 9.5 MeV (9.5106 eV), and heads in the +x direction straight toward a gold nucleus (containing 79 protons and 118 neutrons). The particles are initially far apart, and the gold nucleus is initially at rest. Answer the following questions about the collision.

a)What is the initial momentum of the alpha particle? (You may assume its speed is small compared to the speed of light).

b)What is the final momentum of the alpha particle, long after it interacts with the gold nucleus?

c) What is the final momentum of the gold nucleus, long after it interacts with the alpha particle?


The Attempt at a Solution



i have solved the initial momentum for the gold nucleaus and got <0,0,0> which was true, and the y and z components of the final momentum of the gold nucleus are also 0's, but i couldn't find the x. i need some help with these 3 parts a,b,c Thanks
 
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i think you shold solve it in "routherford" way, not relativistically...

so try to think how to get the velocity from the kinetic energy, then use all the theorem you know, such as conservations of energy and momentum ;)
 
Marco_84 said:
i think you shold solve it in "routherford" way, not relativistically...

so try to think how to get the velocity from the kinetic energy, then use all the theorem you know, such as conservations of energy and momentum ;)

i know that k= 1/2 mv^2 and i have k given but how would i find m? is it the 4/avogadrosnumber?
 

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