I Also in 3D, two reflections make a rotation?

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The discussion centers on the validity of the statement that two reflections in 3D space result in a rotation, contrasting it with a similar 2D scenario where rotations commute. The original proof for 2D does not directly apply to 3D due to non-commuting rotations. Participants reference a problem from "Linear and Geometric Algebra" by Alan Macdonald, which outlines the relationship between reflections and rotations in both dimensions. The inquiry seeks confirmation of the 3D statement's truth before modifying the proof. The conversation concludes with a participant expressing satisfaction with the clarification provided.
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In the plane, two reflections across non-parallel lines make a rotation around the point of intersection of those two lines. But in 3D, do two reflections across non-parallel planes make a rotation around the line of intersection of the two planes?
The easiest proof I know for the 2D statement in the summary does not carry over nicely to the 3D statement since rotations in 3D don't necessarily commute (the 2D proof uses this commuting among rotations in the plane around a common point). Before I then try to modify the proof so that it works, I would like to know whether the statement for 3D is even true. Thanks in advance.
 
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I would refer you to Linear and Geometric Algebra by Alan Macdonald, problem 7.3.9:
7.3.9 (1 rotation ##\equiv ## 2 reflections) a. Show that the composition of two reflections in hyperplanes is a rotation, with the angle of rotation twice the angle between the hyperplanes.
b. Show that a rotation is the composition of two reflections in hyperplanes, with the angle between the hyperplanes half the angle of rotation.

I am not sure how well this matches your question, but I think it does.
 
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Super! It answers my question very well. Thank you, FactChecker!
 
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