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Find matrix representation for rotating/reflecting hexagon

  1. Mar 11, 2015 #1
    1. The problem statement, all variables and given/known data
    Consider the set of operations in the plane that includes rotations by an angle about the origin and reflections about an axis through the origin. Find a matrix representation in terms of 2x2 matrices of the group of transformations (rotations plus reflections) that leaves the snowflake invariant. Is the group Abelian or non-Abelian?

    2. Relevant equations
    R = [cosθ sinθ]
    [-sinθ cosθ]

    Reflection so that x → -x:
    [-1 0][x] = [-x]
    [0 1][y] [y]

    Reflection so that y → -y:
    [1 0][x] = [x]
    [0 -1][y] [-y]

    Abelian: A.B = B.A

    3. The attempt at a solution
    I know that I will be rotating the regular hexagon by increments of 60° so that each time I rotate, the hexagon is invariant. I know that the regular hexagon has 2n = 12 different symmetries, so I will have 12 2x2 matrices in total. I began by constructing my rotated matrices (0°, 60°, 120°, 180°, 240°, and 300°). I know that I will have 6 axes of symmetry to reflect by . . . 3 that stretch from vertex to vertex and 3 that stretch from the midpoint on one side of the hexagon to the opposite.

    I think I am finding that this group will be non-Abelian, but I am not sure. I have calculated the 6 matrices for the rotations but am unsure of what to do next. If I reflect each rotation so that the +x values become -x I get 6 matrices, but those are only for the symmetries along the axes from vertex to vertex. This cannot be correct since I am leaving out the symmetries that exist from midpoint to midpoint. How do I correct my approach so that it includes these symmetries?

    I have a midterm exam in the class this material appears in tomorrow morning and I know for certain that a problem very similar to this one will be on my exam. I went to my professor for help and he explained the general method for solving it, but I need some extra guidance! I am stuck. Please help!
     
  2. jcsd
  3. Mar 11, 2015 #2

    RUber

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    Homework Helper

    What would you need to rotate by to reflect parallel to the edges? Maybe 1/2 of the angle to get from vertex to vertex?
    Reflecting each rotation is not the same as reflecting over a line of symmetry...you need to rotate back when you are done. In that way, the matrices corresponding to opposing vertices will be redundant, so you will only have 3 (as expected) for the vertex-vertex reflections.
     
  4. Mar 11, 2015 #3

    Dick

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    Science Advisor
    Homework Helper

    I'm not exactly sure what you are asking. But you say you know there are 12 elements in the group. The 6 rotations form an abelian subgroup. If you multiply those by ANY reflection ##r## then you will get all 12 group elements. The other reflections are products of a rotation and ##r##. To determine if the group is abelian just check if the rotations commute with ##r##.
     
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