Altered die problem (Probability)

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The discussion centers on calculating the probability that a selected die is altered after rolling "1" twice. The user defines events A (altered die) and B (outcome is 1) and applies Bayes' theorem to find P(A|B). They calculate P(A∩B) as 1/12 and P(B) as 5/9, resulting in P(A|B) = 3/20. The user seeks validation of their solution and alternative approaches to the problem. The conversation emphasizes the application of probability theory in determining outcomes based on given conditions.
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Hello everyone,

I need some help with the following prob:

A bag contains 3 dice, 2 fair and 1 altered with all odd numbers replace with "1". One die is randomly selected and rolled independently twice. If the outcomes of both rolls were "1" and "1", what is the prob that the selected die is the altered die?

Thanks
 
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What have you done?
 
What is the probability of rolling "1" two times in a row with a regular die? What is the probability of rolling "1" two times in a row with an altered die?
 
Altere die problem

Here's what I've done:

Let A= Altered die and B=outcome is 1

then P(A|B) = P(A∩B)/ P(B)
P(A∩B) = 1/12 ( outcome of 3 11's)
P(B)= 5/9 ( total outcome of 1's)

therefore P(A|B) = (1/12)/(5/9) = 3/20

Is this correct? Is there another way to approach this problem?

Thanks!
 
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