Altered die problem (Probability)

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SUMMARY

The discussion centers on calculating the probability of selecting an altered die from a bag containing two fair dice and one altered die, given that the outcomes of two rolls are both "1". The user applies Bayes' theorem, defining events A (selecting the altered die) and B (rolling "1" twice). The calculations yield P(A|B) = 3/20, indicating the probability of the selected die being altered after observing the outcomes. The user seeks confirmation of this result and alternative approaches to the problem.

PREREQUISITES
  • Understanding of Bayes' theorem and conditional probability
  • Familiarity with probability distributions of fair and altered dice
  • Basic skills in probability calculations
  • Knowledge of event notation (e.g., P(A), P(B))
NEXT STEPS
  • Review the derivation of Bayes' theorem in probability theory
  • Explore examples of altered probability distributions in games
  • Learn about the law of total probability and its applications
  • Investigate common pitfalls in probability calculations
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Students of probability theory, mathematicians, and anyone interested in solving complex probability problems, particularly those involving conditional events and altered distributions.

bobsz
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Hello everyone,

I need some help with the following prob:

A bag contains 3 dice, 2 fair and 1 altered with all odd numbers replace with "1". One die is randomly selected and rolled independently twice. If the outcomes of both rolls were "1" and "1", what is the prob that the selected die is the altered die?

Thanks
 
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What have you done?
 
What is the probability of rolling "1" two times in a row with a regular die? What is the probability of rolling "1" two times in a row with an altered die?
 
Altere die problem

Here's what I've done:

Let A= Altered die and B=outcome is 1

then P(A|B) = P(A∩B)/ P(B)
P(A∩B) = 1/12 ( outcome of 3 11's)
P(B)= 5/9 ( total outcome of 1's)

therefore P(A|B) = (1/12)/(5/9) = 3/20

Is this correct? Is there another way to approach this problem?

Thanks!
 

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